n an orthogonal machining with a tool of gº orthogonal rake angle, the uncut chip thickness is 0.2 mm. The chip thickness fluctuates between 0.25 mm and 0 4 mm what is the ratio of the maximum shear angle to the minimum shear angle during machining?

The following data was obtained from an orthogonal cutting test. Rake angle = 20° Depth of cut = 6 mm Feed rate = 0.25 mm/rev Cutting speed = 0.6 m/s Chip length before cutting = 29.4 mm Vertical cutting force = 1050 N Horizontal cutting force = 630 N Chip length after cutting = 12.9 mm Using Merchant's analysis, calculate (a) Magnitude of resultant force, (b) shear plane angle, (c) friction force and friction angle, and (d) various energies consumed.

1.) The rake angle in an orthogonal cutting operation is -5.736°. The chip thickness before the cut is 0.249 mm, and the resulting chip thickness after the cut is 0.762 mm.  The chip thickness ratio is _ 2.) The rake angle in an orthogonal cutting operation is 17.995°. The chip thickness before the cut is 0.254 mm, and the resulting chip thickness after the cut is 0.595 mm.  The shear plane angle is _ degrees. 3.) The rake angle in an orthogonal cutting operation is -2.804°. The chip thickness before the cut is 0.204 mm, and the resulting chip thickness after the cut is 0.556 mm.  The shear strain is _. 4.) Microscopic examination of chips obtained from actual machining operations have revealed that they are produced by _. 5.) Low-carbon steel with 300 MPa tensile strength and 220 MPa shear strength is turned at 2.5 m/s cutting speed on a lathe. Feed (cutting width) is 0.20 mm/rev and depth of cut is 3.0 mm. Rake angle is 5°. The resulting chip ratio = 0.45. The cutting force is _ N…

In turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.

Rake angle=20 degree, Depth of cut=6 mm, Feed rate =0.25mm/rev,Cutting speed=0.6 m/s, chip length before cutting=29.4mm, vertical cutting force= 1050 NHorizontal cutting force=630, chip length after cutting=12.9Using Merchant’s analysis calculate(a) direction and magnitude of resultant force(b) friction force and friction angle(c) shear plane angle

In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fv

Turning Operation In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 4.8 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.43 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement? Hint: Re-arrange the Tm equation to find v in m/min Tm= T.DO.L v.f 1.522

A slab milling operation is performed to finish the top surface of a steel workpiece 250*75 mm*mm. this will be done with a helical milling cutter with 60 mm. diameter and 8 teeth. The cutting conditions are V=30m/min, f = 0.23 mm/tooth, and t= 6 mm. Find; a) The machining time of one pass. b) The metal remove rate.

In a turning operation, cutting speed =200 m/min; feed = 0.25mm mm/rev, and depth of cut = 4.00mm Thermal diffusivity of the work material = 20m mm^2/s and volumetric specific heat =3.5(10^ -3 )J/mm^ 3 -C If the temperature increase above ambient temperature (20degreesC) is the angle measured by a tool-chip thermocouple to be 700degreesC, determine the specific energy for the work material in this operation.

Q1. Calculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation. Answer Q2. A gray cast iron surface 280 wide and 540mm long may be machined either on a vertical milling machine, using a 100mm - diameter face mill having eight inserted HSS teeth, or on a horizontal milling machine using an HSS slab mill with eight teeth on a 200-mm. diameter. Which machine has the faster cutting time? The values of feed per tooth and cutting speed for both processes are 0.4mm/tooth and 80m/min, respectively. The depth of cut = 3.0 mm and assume A and O equal to 5. Answer