Minimize the Boolean expression F=AB’C’+C’D+BD’+A’C using K -map and implement the logic circuit using NAND gates only.
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Minimize the Boolean expression F=AB’C’+C’D+BD’+A’C using K -map and implement the logic circuit using NAND gates only.
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- Convert the following logic gate circuit into a Boolean expression, writing Boolean sub-expressions next to each gate output in the diagram: C DD3-) Simplify the following Logic Function with Karnaugh diagram in Maxterm form and give the final form; Draw with 2 Input NOR gates only F(A,B,C) = A. (B.C + B'.C) + B. (A'.C' + A.C') + (A.B'.C')Logic Gates:* 7404LS (NOT)* 7408LS (AND)* 7432LS (OR)* 7400LS (NAND)* 7402LS (NOR)* 7486LS (EX-OR)Or you can use 74HCxx versions. Task 2: 4 INPUT PRIORITY ENCODERa) Write the truth table.b) Find the outputs in terms of min terms using minimal expression.c) By using K map, find the simple/simplest expression of theoutputs.d) Draw the circuit diagram. (Simulation design will be accepted.)e) Simulate the circuit & explain your results. (Please do notdesign separate simulations for each output. You should design ONEsimulation including all inputs and outputs.)
- An equation in reduced SOP form, is F=AB+B'C+A'C'. I need to draw a logic circuit F using NOT/AND/OR and logoc circuit F using all NAND gates. Thank you for the help. I understood the previous types of gates but I am confused on how to draw these circuits.parity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.a) For the given logic circuit diagram write the program by using the gate level modeling. b) For the given truth table write the program by using the data flow Modelling. c) Write the test bench of the given logic circuit with all possibilities Y1 Y2 Y3 Y4 Y5 Y6 Y7 A2 A1 A0
- An X-input exclusive-OR gate and a Y-input exclusive-OR gate (where X=3, Y=4 have their outputs connected to a 2-input exclusive-NORgate. Do the following:a) Draw the logic diagram and analyze the logic expression of the output (in standard SOPform).b) List out all essential prime implicants.Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).4. For the NOR gate function shown below a) Write the switching expression for the output, F(A,B,C,D) b) Simplify this switching function so that the only gates involved are AND, OR, and NOT gates. c) Draw the logic diagram of this simplified expression using only AND, OR, and NOT gates. am 1, S..pdf DII PrtScn F8 Home F9 End F10 F3 F4 F5 F6 F7 &
- Question: You must only use DIL chips in your design! No logic gates! 4) a BCD adder using 4-bit full adder 74LS83.(c) Figure Q5(c) shows a logic circuit which has three inputs A, B, C and two outputs F and G. i) Obtain the logic expression for the outputs G and F. ii) Redesign the circuit using only 3-to-8 decoder (with active high outputs) and OR gates. G A B F Figure Q5(c)Design a 3-bit counter that counts the following sequence: 7,5, 3. 1.0.7, 5. 3, 1, 0, 7. etc. Using the sequential design technique that starts from a state diagram, draw the state table. minimize the logic. and draw the final circuit. The outputs of logic circuit are 2 = Qo Q1. I, = Qo.Qi + Qo.Qi, Io = Qo.Q2, Cont2 = Qj Q2 Cont1 = Qu Q2. Cont0 = Q2 Qo.Q1. h = Qo.Qi + Qo.Q1, Io = Qo Qz Cont2 = Q, Q2 Contl = Qo Q2 Cont0 = Q2 Qo Qı Ij = Qo.Q, + Q».Qı, Io = Qo. Q2. Cont2 = Qj Q2. Contl = Qo.Q2. Cont) = Q2 L = Qo.Qı. I¡ = Q. Qj + Qu Q Io = Qv.Qz Comt2 = Q, Q, Contl = Q Q2 Cont0 = Q2 !! fefsto How much will be per-product cost and th