Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH₂(g) + 2H₂S(g) → 4H₂(g)+cS₂(g) Use this chemical equation to answer the questions in the table below. Suppose 210. mmol of CH4 and 420. mmol of H₂S are added to an empty flask. How much CH will be in the flask at equilibrium? Suppose 115. mmol of H₂ and 28.8 mmol of CS, are added to an empty flask. How much CH will be in the flask at equilibrium? None. O Some, but less than 210. mmol. ○ 210. mmol. O More than 210. mmol. O None. Some, but less than 28.8 mmol. 28.8 mmol. More than 28.8 mmol.

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Chapter14: Chemical Equilibirum
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Problem 14.19QP: During an experiment with the Haber process, a researcher put 1 mol N2 and 1 mol H2 into a reaction...
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Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like
this:
CH₂(g) + 2H₂S(g) → 4H₂(g)+CS₂(g)
Use this chemical equation to answer the questions in the table below.
Suppose 210. mmol of CH4 and
420. mmol of H₂S are added to an
empty flask. How much CH will be
in the flask at equilibrium?
Suppose 115. mmol of H₂ and
28.8 mmol of CS₂ are added to an
empty flask. How much CH will be
in the flask at equilibrium?
None.
Some, but less than 210. mmol.
O 210. mmol.
More than 210. mmol.
None.
Some, but less than 28.8 mmol.
28.8 mmol.
O More than 28.8 mmol.
Transcribed Image Text:Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH₂(g) + 2H₂S(g) → 4H₂(g)+CS₂(g) Use this chemical equation to answer the questions in the table below. Suppose 210. mmol of CH4 and 420. mmol of H₂S are added to an empty flask. How much CH will be in the flask at equilibrium? Suppose 115. mmol of H₂ and 28.8 mmol of CS₂ are added to an empty flask. How much CH will be in the flask at equilibrium? None. Some, but less than 210. mmol. O 210. mmol. More than 210. mmol. None. Some, but less than 28.8 mmol. 28.8 mmol. O More than 28.8 mmol.
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