mber of nodes in the strongest linkedlist is unkno

Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node.

Can somebody tell me the answer to this?

Using a comparison of each node's key, create a procedure for eradicating duplicates from a linked list.

In python. Write a LinkedList class that has recursive implementations of the add and remove methods. It should also have recursive implementations of the contains, insert, and reverse methods. The reverse method should not change the data value each node holds - it must rearrange the order of the nodes in the linked list (by changing the next value each node holds). It should have a recursive method named to_plain_list that takes no parameters (unless they have default arguments) and returns a regular Python list that has the same values (from the data attribute of the Node objects), in the same order, as the current state of the linked list. The head data member of the LinkedList class must be private and have a get method defined (named get_head). It should return the first Node in the list (not the value inside it). As in the iterative LinkedList in the exploration, the data members of the Node class don't have to be private. The reason for that is because Node is a trivial class…

Given a circular linked list in which the last node is connected to the first node. If we set a node curr equal to first node at the start of traversal and we start traversing the circular linked list, the condition to check if we have reached the end of the list then becomes curr = first curr.next == null curr.next.next == first curr.next == first None of the Above

how to fix the error in the remove function (c++) struct LinkedList {public:LinkedList () : head_(0) {};~LinkedList () { delete_nodes (); }; // returns 0 on success,-1 on failureint insert (const int &new_item) {return ((head_ = new Node(new_item, head_)) != 0) ? 0 : -1; }// returns 0 on success, -1 on failureint remove (const int &item_to_remove) {Node *marker = head_;Node *temp = 0; // temp points to one behind as we iteratewhile (marker != 0) {if (marker->value() == item_to_remove) {if (temp == 0) { // marker is the first element in the listif (marker->next() == 0) {head_ = 0;delete marker; // marker is the only element in the listmarker = 0;} else {head_ = new Node(marker->value(), marker->next());delete marker;marker = marker->next(); }return 0;} else {temp->next (marker->next());delete temp;temp = 0;return 0; } }// marker = 0; // reset the markertemp = marker;marker = marker->next(); }return -1; // failure }void print (void) {Node *marker =…

We can iterate over a hash map using a for-each loop directly. (Exactly like we can over a LinkedList or an ArrayList). True or False

JAVA please Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts Code provided in the assignment ItemNode.java:

In a circular linked list, how can you determine if a given node is the last node in the list? Describe the approach you would take to solve this problem.