
Concept explainers
Mapping three genes in a single cross: generic a, b, c mutant loci (a+, b+, c+ = wild type).
a, b, c x a, b, c
a+, b+, c+ a, b, c
Offspring: a, b, c = 870
a+, b+, c+ = 855
a+, b, c = 65
a, b+, c+ = 63
a+, b+, c = 67
a, b, c+ = 65
a+, b, c+ = 8
a, b+, c = 7
Determine the map distance between each gene and draw a map showing the map distance and the order of the three genes.

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