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- An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current 1 = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm², and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (t, = 800 for iron).An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm², and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (ur = 800 for iron).An iron circuit with a small0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (u, = 800 for iron). Figure 1
- 11. There is 900 mA of current through a wire with 40 turns. What is the reluctance of the circuit if the flux is 400Wb? 14,400 At/Wb B 1,440 At/Wb Ⓒ9,000 At/Wb O90,000 At/Wb Answer: Option O Explanation: No answer description is available. Let's discuss.The 'skin effecť is a phenomenon experienced when current flows through a metal. Which two of the following statements are correct? 15 Select one or more: O a. A smaller 'skin depth' implies a higher resistance O b. Direct current can cause the skin effect O c. The skin depth is smaller in highly conductive metals O d. The skin depth is larger in metals with high magnetic permeabilityThe length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft iron core has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20mm. Take the relative permeability of soft iron as 1100. Determine the total flux
- An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm?, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (4, = 800 for iron). Figure 1A current in a 250 turn coil is 2.25A, wound in a core that has a reluctance of 12,000 AT/Wb. What is the resulting flux density (in Tesla), if the area of the core is 8cm²?The parallel magnetic circuit should in Figure 1 is silicon steel area throughout, S = 1.30 cm². The mean lengths are 1₁ have 50 turns each. = 13 I with the same cross-sectional = 25 cm, 1₂ = 5 cm. The coils 1₂ Figure 1 a) Given that ₁ = 90 μ Wb and 3 = 120 μ Wb, find the coil currents. b) Obtain the equivalent magnetic circuit using reluctances for three legs, and calculate the flux in the core using F₁ = 19.3 A and F₂ = 37.5 A.
- (3.4)The length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft-iron core has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20 mm. Take the relative permeability of soft iron as 1100. 3.4.1) Determine the magnetomotive force in the core 3.4.2)Determine the field strength 3.4.3) Determine the total fluxA)The left hand rule for a coil is such that if you were to hold a coil in your left hand with your fingers pointing in the direction of the electron flow, your thumb would point in the direction of thea) electron flow b) flow lines c) face of the north pole d) none of the above. B) What is a magnetic flux line?a) It is the space around a magnet or the space in which the magnetic forces act.b) It is the magnetic force that has a definite direction at all points along a curved line from the north to south pole.c) It is the ability of a magnetic material to be easily magnetized.d) none of the above C)It is believed that a magnetic material is .........a) consists of a single large magnetic molecule b) is composed of many tiny magnetic molecules c) consists of a single non-magnetic molecule d) none of the above1. What is the reluctance of 10 cm diameter silicon steel of 2500 permeability with a mean length of 20 cm? A. 0.000201 cgs B. 0.000102 cgs C. 0.000212 cgs D. 0.000123 cgs 2. At what rate the flux must be varied to measure 12 V across the terminal of 300 turns coil? A. 0.05 Wb/s B. 0.04 Wb/s C. 0.03 Wb/s D 0.02 Wb/s