Find the missed data and give the result of Fineness Modulus of sample soil data given below.WeightPercentageCumulativePercentage finerSieveretainedWeight retainedpercentageN = (100 - C)S.NOsizeretained (C)Select one:(gm)(gm)O a. 7.824175mmO b. 9.43863mmO c. 8.142350mmO d. 7.649437.5mm28mm1236.156.15620mm1075.3511.50714mm20810.421.9810mm562.824.76.3mm3.9105.0mm924.633.2113.35mm30815.448.6122.0mm22311.1559.75131.18mm1889.469.1514600µ28214.183.2515300µ964.888.0516150µ884.492.451775µ1035.1597.618pan482.4100

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Find the missed data and give the result of Fineness Modulus of sample soil data given below. Weight Percentage Cumulative Percentage finer Sieve retained Weight retained percentage N = (100 - C) S.NO Select one: O a. 7.824 size retained (C) (gm) (gm) 75mm O b. 9.438 2 63mm O c. 8.142 3 50mm O d. 7.649 4 37.5mm 5 28mm 123 6.15 6.15 6 20mm 107 5.35 11.50 7 14mm 208 10.4 21.9 8 10mm 56 2.8 24.7 9 6.3mm 3.9 10 5.0mm 92 4.6 33.2 11 3.35mm 308 15.4 48.6 12 2.0mm 223 11.15 59.75 13 1.18mm 188 9.4 69.15 14 600µ 282 14.1 83.25 15 300µ 96 4.8 88.05 16 150µ 88 4.4 92.45 17 75µ 103 5.15 97.6 18 pan 48 2.4 100

Find the missed data and give the result of Fineness Modulus of sample soil data given below. Weight Percentage Cumulative Percentage finer Sieve retained Weight retained percentage N = (100 - C) S.NO Select one: O a. 7.824 size retained (C) (gm) (gm) 75mm O b. 9.438 2 63mm O c. 8.142 3 50mm O d. 7.649 4 37.5mm 5 28mm 123 6.15 6.15 6 20mm 107 5.35 11.50 7 14mm 208 10.4 21.9 8 10mm 56 2.8 24.7 9 6.3mm 3.9 10 5.0mm 92 4.6 33.2 11 3.35mm 308 15.4 48.6 12 2.0mm 223 11.15 59.75 13 1.18mm 188 9.4 69.15 14 600µ 282 14.1 83.25 15 300µ 96 4.8 88.05 16 150µ 88 4.4 92.45 17 75µ 103 5.15 97.6 18 pan 48 2.4 100

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Situation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No 4 4.760 99 No. 8 2.380 91 No. 10 2.000 90 No. 20 0.840 85 No. 40 0.420 81 No. 60 0.250 79 No. 100 0.150 67 No. 200 0.075 60 Characteristics of No. 40 Fraction LL 39 PL 32 General classification Granular materials (35% or less of total sample passing No. 200) A-1 A-2 Group classification Sieve analysis (percent passing) No. 10 A-1-a A-1-b A-3 A-2-4 A-2-5 A-2-6 A-2-7 50 max. 30 max. 15 max. No. 40 50 max. 25 max. 51 min. 10 max. No. 200 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 10 max. 41 min. 40 max. 11 min. 41 min. 11 min. 6 max. NP 10 max. Usual types of significant constituent Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand materials ESC F4 FS F6 F7 FB F9 & 61 A4TECH Y P G J K 国因

The results of the sieve analysis of soil A is tabulated below. Classify the soil according to AASHTO classification system and unified soil classification systems (USCS). Diameter (mm) 4.75 2.0 0.85 0.425 0.150 0.075 LL PL % Passing 100 93 85 80 55 50 18 70
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Percent Passing 4 4.760 100 6 2.380 91 10 2.000 88 20 0.840 76 40 0.420 55 60 0.250 50 100 0.150 47 200 0.075 46 Characteristics of No. 40 Fraction LL 50 PL 34
K1
- My courses > Soil-20-21 > Topic 3: Soil Compaction > Compaction Quiz The data in the table below was gotten from modified Proctor test for a soil sample having G,-2.62 w (%) 10 12 14 17 19 23 1.15 1.07 0.94 0.83 0.88 0.92 What is the degree of compaction if the field dry unit weight is 13.2 kN/m' and field moisture content is 9% ? O a. 71.3% Ob. 100% Oc. 94% Od. 80%
Situation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
How to solve the problem, may I request to put an explanation every step ?, Thank you so much.
Make comments about the general properties of the soil by classifying the floors given in the figures in the laboratory test results according to AASHTO and UCSC.
SG is 2.66 and temperature is 18 degrees celcius
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