A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.72 mm the values of elastic modulus for steel is 223 MPa. Take H1 = 7 cm, H2 = 10 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar.i) Magnitude Force, P = ii) Stress-induced in the top bar = iii) Stress-induced in the bottom bar = R cm x RcmSteel barH1 cmQ cm x Q cmŠteel barH2 cm

Given ∆LAC=0.72mmE=223 MPa=223 N/m2=223 ×10-4 N/cm2H1=LAB=7 cmH2=LBC=10 cmArea of bar AB=AAB=2×2=4…

Answered: A member is formed by connecting two…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.72 mm the values of elastic modulus for steel is 223 MPa. Take H₁ = 7 cm, H₂ = 10 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar.

i) Magnitude Force, P =

ii) Stress-induced in the top bar =

iii) Stress-induced in the bottom bar =

R cm x Rcm
Steel bar
H1 cm
Q cm x Q cm
Šteel bar
H2 cm

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