Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true. a. P(tzto) = .025, where df = 11 b. P(tzto) =.01, where df = 18 c. P(tsto) =.005, where df = 6 - X Data table d. P(tsto) =.05, where df = 13 E Click the icon to view the table of critical values of t. Degrees of freedom tos0 t025 to10 too5 a. The value of to is 1 6.314 12.706 31.821 63.657 2.920 4.303 6.965 9.925 b. The value of to is 2.353 3.182 4.541 5.841 4 2.132 2.776 3.747 4.604 c. The value of to is 2.015 2.571 3.365 4.032 6 1.943 2.447 3.143 3.707 d. The value of to is s. 7 1.895 2.365 2.998 3.499 8. 1.860 2.306 2.896 3.355 9 1.833 2.262 2.821 3.250 10 1.812 2.228 2.764 3.169 11 1.796 2.201 2.718 3.106 12 1.782 2.179 2.681 3.055 13 1.771 2.160 2.650 3.012 14 1.761 2.145 2.624 2.977 15 1.753 2.131 2.602 2.947 16 1.746 2.120 2.583 2.921 17 1.740 2.110 2.567 2.898 18 1.734 2.101 2.552 2.878 19 1.729 2.093 2.539 2.861 20 1.725 2.086 2.528 2.845 Next Print Done

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true.
a. P(t2to) = .025, where df = 11
b. P(t2to) = .01, where df = 18
P(tst)
d. P (tsto) = .05, where df = 13
%3D
%3D
с. Р
= .005, where df = 6
Data table
Click the icon to view the table of critical values of t.
Degrees of
freedom
t.050
t.025
t010
t.005
a. The value of to is
1
6.314
12.706
31.821
63.657
2
2.920
4.303
6.965
9.925
b. The value of to is
3
2.353
3.182
4.541
5.841
4
2.132
2.776
3.747
4.604
c. The value of to is
2.015
2.571
3.365
4.032
1.943
2.447
3.143
3.707
d. The value of to is
7
1.895
2.365
2.998
3.499
8.
1.860
2.306
2.896
3.355
1.833
2.262
2.821
3.250
10
1.812
2.228
2.764
3.169
11
1.796
2.201
2.718
3.106
12
1.782
2.179
2.681
3.055
13
1.771
2.160
2.650
3.012
14
1.761
2.145
2.624
2.977
15
1.753
2.131
2.602
2.947
16
1.746
2.120
2.583
2.921
17
1.740
2.110
2.567
2.898
18
1.734
2.101
2.552
2.878
19
1.729
2.093
2.539
2.861
20
1.725
2.086
2.528
2.845
Next
Print
Done
Transcribed Image Text:Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true. a. P(t2to) = .025, where df = 11 b. P(t2to) = .01, where df = 18 P(tst) d. P (tsto) = .05, where df = 13 %3D %3D с. Р = .005, where df = 6 Data table Click the icon to view the table of critical values of t. Degrees of freedom t.050 t.025 t010 t.005 a. The value of to is 1 6.314 12.706 31.821 63.657 2 2.920 4.303 6.965 9.925 b. The value of to is 3 2.353 3.182 4.541 5.841 4 2.132 2.776 3.747 4.604 c. The value of to is 2.015 2.571 3.365 4.032 1.943 2.447 3.143 3.707 d. The value of to is 7 1.895 2.365 2.998 3.499 8. 1.860 2.306 2.896 3.355 1.833 2.262 2.821 3.250 10 1.812 2.228 2.764 3.169 11 1.796 2.201 2.718 3.106 12 1.782 2.179 2.681 3.055 13 1.771 2.160 2.650 3.012 14 1.761 2.145 2.624 2.977 15 1.753 2.131 2.602 2.947 16 1.746 2.120 2.583 2.921 17 1.740 2.110 2.567 2.898 18 1.734 2.101 2.552 2.878 19 1.729 2.093 2.539 2.861 20 1.725 2.086 2.528 2.845 Next Print Done
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