KHP(aq) + NaOH(aq) -> H2O (l) + KNaP(aq) 1. Once the equivalence point is reached, any NaOH that is added after that reacts with the indicator giving the pink color. If too much NaOH is added the pink color is too dark. How would this affect the value of the calculated NaOH molarity? 2. Why might it be a good idea to rinse down the sides of the flask with a squirt of deionized water from time to time during the titration? 3. When a little NaOH is added to the KPH solution, why is a pink color initially seen, but then it disappears?
KHP(aq) + NaOH(aq) -> H2O (l) + KNaP(aq) 1. Once the equivalence point is reached, any NaOH that is added after that reacts with the indicator giving the pink color. If too much NaOH is added the pink color is too dark. How would this affect the value of the calculated NaOH molarity? 2. Why might it be a good idea to rinse down the sides of the flask with a squirt of deionized water from time to time during the titration? 3. When a little NaOH is added to the KPH solution, why is a pink color initially seen, but then it disappears?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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KHP(aq) + NaOH(aq) -> H2O (l) + KNaP(aq)
1. Once the equivalence point is reached, any NaOH that is added after that reacts with the indicator giving the pink color.
If too much NaOH is added the pink color is too dark. How would this affect the value of the calculated NaOH molarity?
2. Why might it be a good idea to rinse down the sides of the flask with a squirt of deionized water from time to time during the titration?
3. When a little NaOH is added to the KPH solution, why is a pink color initially seen, but then it disappears?
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