A 10.0 mL solution of 0.720 M NH3 is titrated with a 0.240 M HCl solution. Calculate the pH after the following additions of the HCl solution: 0.00 mL, 10.0 mL, 30.0 mL, and 40.0 mL. Round your answer to 3 decimal places. Note: Reference the K of acids at 25 °C and K, of bases at 25 °C tables for additional information. Part 1 of 4 0.00 mL Added, pH = Part 2 of 4 10.0 mL Added, pH = Part 3 of 4 30.0 mL Added, pH = □ x10 X X X S S

Chemistry: The Molecular Science
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Chapter15: Additional Aqueous Equilibria
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10B6. Answer all parts to this question.
A 10.0 mL solution of 0.720 M NH3 is titrated with a 0.240 M HCl solution. Calculate the pH after the following additions of the HCl solution: 0.00 mL,
10.0 mL, 30.0 mL, and 40.0 mL. Round your answer to 3 decimal places.
Note: Reference the K of acids at 25 °C and K of bases at 25 °C tables for additional information.
Part 1 of 4
0.00 mL Added, pH =
Part 2 of 4
10.0 mL Added, pH
Part 3 of 4
30.0 mL Added, pH =
0
x10
Transcribed Image Text:A 10.0 mL solution of 0.720 M NH3 is titrated with a 0.240 M HCl solution. Calculate the pH after the following additions of the HCl solution: 0.00 mL, 10.0 mL, 30.0 mL, and 40.0 mL. Round your answer to 3 decimal places. Note: Reference the K of acids at 25 °C and K of bases at 25 °C tables for additional information. Part 1 of 4 0.00 mL Added, pH = Part 2 of 4 10.0 mL Added, pH Part 3 of 4 30.0 mL Added, pH = 0 x10
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