It would seem that since the force of gravity is responsible for the acceleration of a pendulum bob, that a larger mass would have a larger acceleration and so "swing faster," that is have a shorter period of oscillation. Why is the period of the pendulum bob independent of its mass?

The time period of a simple pendulum is 1.4 s if we now increase the length 50% how long will it take for one complete swing

The mass on the end of a pendulum is 0.04 kg and hangs from a string of length 1.2 m. The pendulum is raised to point Q, which is 0.10 m above its lowest position, and released so that it oscillates between the points P and Q as shown below. Describe one modification that could be made to double the period of oscillation.

A spring (k = 64.0 N/m ) hangs vertically with its top end fixed. A mass attached to the bottom of the spring then displaces it 0.285 m , establishing a new equilibrium. Given that, though, If the mass is further displaced and then released, can you explain how to get the period of the resulting oscillations that explains the concept?