iR 200 Ω 250 mH ic + VC 16 uF 9. For the parallel RLC circuit shown on the previous page, vc(0) - 40 V and iz (0) the following. (a) in(0) and ic(0). (b) uc(t) for t>0. Table 8.2 comes in very handy here. - 10 mA. Find (c) i(t) fort >0. You know the voltage across the capacitor (answer to part (b)) which is the same as the voltage across the inductor. Knowing how i and v are related for an inductor, you can then find the current from the voltage. This involves an integral that wouldn't be pleasant to do on your own. However, feel free to use a tool such as WolframAlpha to perform this integration.

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iR
200 Ω
250 mH
ic
+
VC 16 uF
Transcribed Image Text:iR 200 Ω 250 mH ic + VC 16 uF
9. For the parallel RLC circuit shown on the previous page, vc(0) - 40 V and iz (0)
the following.
(a) in(0) and ic(0).
(b) uc(t) for t>0. Table 8.2 comes in very handy here.
-
10 mA. Find
(c) i(t) fort >0. You know the voltage across the capacitor (answer to part (b)) which is the
same as the voltage across the inductor. Knowing how i and v are related for an inductor, you
can then find the current from the voltage. This involves an integral that wouldn't be pleasant
to do on your own. However, feel free to use a tool such as WolframAlpha to perform this
integration.
Transcribed Image Text:9. For the parallel RLC circuit shown on the previous page, vc(0) - 40 V and iz (0) the following. (a) in(0) and ic(0). (b) uc(t) for t>0. Table 8.2 comes in very handy here. - 10 mA. Find (c) i(t) fort >0. You know the voltage across the capacitor (answer to part (b)) which is the same as the voltage across the inductor. Knowing how i and v are related for an inductor, you can then find the current from the voltage. This involves an integral that wouldn't be pleasant to do on your own. However, feel free to use a tool such as WolframAlpha to perform this integration.
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