INSTRUCTIONS: Solve the following problem by manually applying the finite element method, following these steps: Pre-processing: Geometry identification. Material properties identification. Load identification. Boundary condition identification. Development of the connectivity matrix for nodes and elements. Processing: Calculation of local stiffness matrices. Assembly of the global stiffness matrix. Assembly of the global force matrix (if required). Application of boundary conditions. Resolution of the system of equations. Derivation of the complete displacement vector (u). Post-processing: Reaction forces calculation. Stress analysis. Problem Statement: the truss nodes and elements (in parentheses) are already numbered. The areas (are in cm^2 ) are underlined. members are made of structural steel, modulus of elasticity is (E) of 20×10^6 N/cm^2 . the lengths are given in cm.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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INSTRUCTIONS: Solve the following problem by manually applying the finite element method, following these steps:

Pre-processing:

  1. Geometry identification.
  2. Material properties identification.
  3. Load identification.
  4. Boundary condition identification.
  5. Development of the connectivity matrix for nodes and elements.

Processing:

  1. Calculation of local stiffness matrices.
  2. Assembly of the global stiffness matrix.
  3. Assembly of the global force matrix (if required).
  4. Application of boundary conditions.
  5. Resolution of the system of equations.
  6. Derivation of the complete displacement vector (u).

Post-processing:

  1. Reaction forces calculation.
  2. Stress analysis.

Problem Statement: the truss nodes and elements (in parentheses) are already numbered. The areas (are in cm^2 ) are underlined. members are made of structural steel, modulus of elasticity is (E) of 20×10^6 N/cm^2 . the lengths are given in cm.

80 cm
(1)
501
(2)
12
3
60 cm=
50000 N
30°
Transcribed Image Text:80 cm (1) 501 (2) 12 3 60 cm= 50000 N 30°
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