Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Choose one equation (and only one) from the equation sheet that would let you solve the problem posed. Then define which variables in the equation go with what numbers from the problem itself (not from other problems), and define which variable is
being solved for. Do not actually solve the problem numerically or algebraically, just pick the one equation and define the relevant knowns and single unknown. Don’t forget to include direction when called for by a vector variable
11) During a particular time interval an air conditioner requires 1.2 kJ of mechanical
energy in order to remove 2.7 kJ of heat from inside a house, dumping 3.9 kJ of heat outside of the house in the process. How good is it at its job?
Transcribed Image Text:x(t) = x0 + Voxt + ½ axt²
y(t) = yo + Voyt + ½ ayt²
Vx (t) = Vox? + 2ax(x-xo)
Vy (t) = Voy + 2a,(y-yo)
v(t) = dx/dt
a(t) = d?x/dt?
Vx(t) = Vox + axt
Vy(t) = Voy + ayt
<V> = (vo + V1) / 2
<a> = (V1 – Vo)/(tj – to)
r = x² + y?
(Vo + V1) / 2 = Ar/At
a(t) = dv/dt
x = rcose
<V> = Ar/At
<a> = Av/At
|A| = (A,? + A,?)2
 = A
y = rsin0
a = ac(-f) + arê®
ac = Vr/r
a. = m²r
VT = (2nr)/T
ac = 4n°r/T?
ar = dvf/dt
VT = or
f = o/2n
f = 1/T
rP/A = rP/B + rB/A
VP/A = VP/B + VB/A
ap/A = ap/B + aB/A
m, m2
EF¡ = ma
F12 = -F21
= G
(-12)
fs,max = lsFN
F = mv²/r
fk = µkFN
Fe = mac
Fdrag
= -by
Fdrag = ½ DpAv² (-8)
2mg
Vt = mg/b
Vt =
dW; = F; · dr
Wi = F; · Ar
Ug = mgy
AUint = fgAs
n = Pout/Pin (X 100%)
V DpA
K = ½ mv?
Usp = ½ k(x-xrel)?
P = dW/dt
AK = ½ m (v1²-vo²)
Fsp = -k (x-Xrel)
P = dU/dt
= dp/dt
ΣW ΔΚ
P = F•v
<ΣF-Δp/Δt
p= mv
miv10 + m2v20 = m¡v11 + m2V21
½ miV10? + ½ m2V20? = ½ m¡V11? + ½ m2v21?
m¡V10 + m2v20 = (m¡+m2)VTI
(mi+m2)VT0 = m¡Vj1 + m2V21
(m2-m1
m,+m2
(Em;) Zem = E(m;z;)
(mi-m2) V10 +
m1+m2/
2m2
2m1
V11
V20
V21 =
V20 +
|V10
\m,+m2/
(Σm) xem- Σ(mx )
Av, = +Ve In(M/M¡)
0 = 0o + @ot + ½ at²
\m,+m2/
(Σm ) yem Σ(my )
Fth = v(dm/dt)
mtotalXCM =
o? = 00? + 2a(0–0)
@ = Wo + at
<a> = A@/At
<@> = AÐ/At
Vcm = ro
S = r0
a(t) = d²0/dt?
T = rleverF
TAB = -TBA
I= Iem + Md²
@(t) = d0/dt
a(t) = d@/dt
T = rFsino
Et = dL/dt
I = BMR?
L =r xp
T =r x F
dW; = t;· de
I= E m,r;?
Op = (mgrsin0)/(Io)
Στ-Ια
Krot = ½ Io?
rjever = rsino
I010 + I2020 = I011 + I2021
(I1+I2)@ro = I10i1 + I2@21
L = Io
ΔL TΔt
I010 + I2020 = (I1+I2)@T1
I10010 = I1101
1/2
![F
ΔF
ΔΡ
Y =
B =
B =
AV
S =
Vo
x(t) = Xmax cOs(@t + 0)
T= 27 (L/g)'2
@ = (k/m)'2
T= 27 (I/mgd)"2
Vmax = OXmax
amax = 0ʻxmax
y(x,t) = ymax Ssin(kx + @t + þ)
v = f.
a?y
Odamped = ( (k/m) – (b/2m)² )'/²
y(x,t) = ymax sin(kx - ot + ¢)
2 = 2n/k
v = @/k
1 д?у
v = (Fr/u)2
µ = m/L
<Pwave> = ½ uymax-@ʻv
əx²
v² at2
ΔΡ
%3D
max
Bksmax AP,
= pwvsSmax
Vsound =
Vsound = 343 m/s
max
TC
Vsound =
(331-) 1+
Vsound 331 m/s + (0.60 m/s°C) Tc
273 °C
APmax
I =
2ρν
10 dB = 1 B
<P>
B = log ()
P = pvosmax A sin°(kx-@t)
I, = 10-12 W/m² (exactly)
I =
%3D
4tr2
fobserver = fsource
(Vsound+Vobserver
sin(A) + sin(B) = 2 cos (-4):
sin ()
Vsound-Vsource
0 = 2tn (const)
0 = T(2n+1) (dest)
An = 4L/(2n-1)
fn = (2n-1)v/4L
AV = V.B(T1-To) AL=La(T1-To)
Q = mLv
AEint = W + Q
n = 0, ±1, ±2,..
An = 2L/n
fn = nv/2L
n = 1, 2, 3, ...
Af = |f1 – f2|
B= 3a
Q = mLf
AEcyele
PV = nRT
Q = mcAT
W = - SP dV
AT = Tinal - Tinitial
Wisobaric = -PAV
Vfinal
\Vinitial-
= 0
Wisovolumetric = 0
Qadiabatic = 0
Qisothermal
= nRT In
R = Ax/k
4
Pradiated = GAETK*
TK = Tc + 273.15
Ktot = ( ½ NKBT) * degrees of freedom (dof)
8kgT
P = kA|dT/dx|
Pnet = GAe (Tsource – Tobject")
½ mo<v?> = ½ kgT
3kgT
kB = R/NA
2kgT
VRMS =
Vavg
Vmost likely
mo
Timo
V mo
3RT
8RT
2RT
VRMS =
Vavg
Vmost likely
M
M
AEint = Q = nCyAT Q=nCpAT
P¡V = P2V2Y
CoP = |Q/|W|
dS = dQreversible/T ASfree expand = nR In(V2/V1)
Ср 3D Су + R
Y = Cp/Cy
n = |W]/lQH|
Cy = ½ R * dof
T¡V;! = T2V;*1
n = 1 – (IQc/IQH|)
Notto = 1– (V2/V)-!
= 0
NCarnot = 1 – (T/TH)
ASCarnot
%3D](https://content.bartleby.com/qna-images/question/5fb1edcb-e378-4007-8f8b-0be0a89cb7b5/24054b34-9d03-4c69-8a6e-0668c972023d/320vkic_processed.jpeg)
Transcribed Image Text:F
ΔF
ΔΡ
Y =
B =
B =
AV
S =
Vo
x(t) = Xmax cOs(@t + 0)
T= 27 (L/g)'2
@ = (k/m)'2
T= 27 (I/mgd)"2
Vmax = OXmax
amax = 0ʻxmax
y(x,t) = ymax Ssin(kx + @t + þ)
v = f.
a?y
Odamped = ( (k/m) – (b/2m)² )'/²
y(x,t) = ymax sin(kx - ot + ¢)
2 = 2n/k
v = @/k
1 д?у
v = (Fr/u)2
µ = m/L
<Pwave> = ½ uymax-@ʻv
əx²
v² at2
ΔΡ
%3D
max
Bksmax AP,
= pwvsSmax
Vsound =
Vsound = 343 m/s
max
TC
Vsound =
(331-) 1+
Vsound 331 m/s + (0.60 m/s°C) Tc
273 °C
APmax
I =
2ρν
10 dB = 1 B
<P>
B = log ()
P = pvosmax A sin°(kx-@t)
I, = 10-12 W/m² (exactly)
I =
%3D
4tr2
fobserver = fsource
(Vsound+Vobserver
sin(A) + sin(B) = 2 cos (-4):
sin ()
Vsound-Vsource
0 = 2tn (const)
0 = T(2n+1) (dest)
An = 4L/(2n-1)
fn = (2n-1)v/4L
AV = V.B(T1-To) AL=La(T1-To)
Q = mLv
AEint = W + Q
n = 0, ±1, ±2,..
An = 2L/n
fn = nv/2L
n = 1, 2, 3, ...
Af = |f1 – f2|
B= 3a
Q = mLf
AEcyele
PV = nRT
Q = mcAT
W = - SP dV
AT = Tinal - Tinitial
Wisobaric = -PAV
Vfinal
\Vinitial-
= 0
Wisovolumetric = 0
Qadiabatic = 0
Qisothermal
= nRT In
R = Ax/k
4
Pradiated = GAETK*
TK = Tc + 273.15
Ktot = ( ½ NKBT) * degrees of freedom (dof)
8kgT
P = kA|dT/dx|
Pnet = GAe (Tsource – Tobject")
½ mo<v?> = ½ kgT
3kgT
kB = R/NA
2kgT
VRMS =
Vavg
Vmost likely
mo
Timo
V mo
3RT
8RT
2RT
VRMS =
Vavg
Vmost likely
M
M
AEint = Q = nCyAT Q=nCpAT
P¡V = P2V2Y
CoP = |Q/|W|
dS = dQreversible/T ASfree expand = nR In(V2/V1)
Ср 3D Су + R
Y = Cp/Cy
n = |W]/lQH|
Cy = ½ R * dof
T¡V;! = T2V;*1
n = 1 – (IQc/IQH|)
Notto = 1– (V2/V)-!
= 0
NCarnot = 1 – (T/TH)
ASCarnot
%3D
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