A body moves from: position (1.0 m)i− (3.0 m)j where its velocity is (2.0 m/s)i+ (0.5 m/s)j to position (−1.0 m)i+ (1.0 m)j where its velocity is (4.0m/s)i Express the body’s displacement (vector) delta r. Express the body’s change in velocity (vector) delta v.

A particle leaves the origin with an initial velocity 3.00î m/s and a constant acceleration ở -1.00î – 0.50ĵ m/s². When it reaches its maximum x coordinate, what are its (a) velocity and (b) position vector?

A proton initially has 7 = (-7.10)î + (5.10)Ƒ + (−6.60)î : and then 2.70 s later has 7 = (4.70)î + (5.10)ĵ + (13.0)ê (in avg meters per second). (a) For that 2.70 s, what is the proton's average acceleration a in unit vector notation, (b) in magnitude, and the angle between a and the positive direction of the x axis? avg (a) Number i 11.8 (b) Number i (c) Number i î+ Units Units i 19.6 k Units m/s

Given the position vector ~r(t) = t^2ˆi+tˆj in meters, what is the magnitudeof the velocity vector at a time of three seconds?