In the structural beam segment AD shown in the figure, a triangularly distributed load which varies from 0 to 6 kN/m applies and the support reaction at A is 5.5 kN. The shear force and bending moment at the point D are,
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- The shear-force diagram for a beam is shown in the figure. Assuming that no couples act as loads on the beam, determine the forces acting on the beam and draw the bending-moment diagram.Find expressions for shear force V and moment M at x = L/2 of beam BC. Express V and M in term s of peak load intensity q0and be a m length variable L.The horizontal beam ABC of an oil-well pump has the cross section shown in the figure. If the vertical pumping force acting at end C is 9 kips and if the distance from the line of action ofthat force to point B is 16 ft, what is the maximum bending stress in the beam due to the pumping force?
- A beam supporting a uniform load of intensity q throughout its length rests on pistons at points A, C and B (sec figure). The cylinders are filled with oil and are connected by a tube so that the oil pressure on each piston is the same. The pistons at A and B have diameter d1and the piston at C has diameter D2. (a) Determine the ratio of d2to d1so that the largest bending moment in the beam is as small as possible. Under these optimum conditions, what is the largest bending moment Mmaxin the beam? What is the difference in elevation between point C and the end supports?In the structural beam segment AD shown in the figure, a triangularly distributed load which varies from 0 to 6 kN/m applies and the support reaction at A is 5.5 kN. The shear force and bending moment at the point D are, 0-6 kN/m 3 m O a. (-)3.5 kN, 11.5 kNm O b. (-)12.5 kN, 7.5 kNm O c. (-)2.5 kN, 11.5 kNm O d. (-)3.5 kN, 7.5 kNmThe figure shows a propped up horizontal cantilever beam carrying a 1kN load at the end. The shear force in the beam segment BC at any point is, 1 kN B 0.5 m 0.5 m O a. Statically indeterminate O b.0 O. (- )1 kN O d. (+) 1 kN
- Draw the Shear force diagram & Bending moment diagram for the cantilever beam as shown in figure, mark the salient points in the diagram. Neglect the self-weight of the beam, where F, =25 N, F2 =40N, F3 =30 N, F4 =20N, a =5 m, b=2 m, c=4 m, d=4 m F4 F3 F2 F1 E D A d. b a (Enter only the values in the boxes by referring the units given in bracket. Also upload the hand written answer in the link provided) (i) The reaction at the fixed support "A" (unit in N)=_ (ii) Shear force at the point "A" (Unit in N) = %3D (iii) Shear force at the point "E" (Unit in N) = %3DDetermine the support reactions at the the fixed support, A. Neglect the weight and size of the beam. Given data: Distributed load W=50 N/m; Couple C=160 N-m; and the point load P-780 N acting inclined at an angle of 35 in degree with respect to horizontal. W (n/m) P C (N.m) 1.5 m 2 m 4 m Horizontal force component at A along x, AxD Horizontal force component at A along y, Ay= Moment component at A, Ma= N. mDraw the Shear force diagram & Bending moment diagram for the cantilever beam as shown in figure, mark the salient points in the diagram. Neglect the self-weight of the beam, where F1 =10 N, F2 =60N, F3 =30 N, F4 =10N, a =5 m, b=2 m, c=3 m, d=5 m F4 F3 F2 F1 E A d. a
- The beam with the loading as shown in the figure is fixed at A and simply supported at B. Determine the magnitude of the reaction moment at A if the vertical reactions forces at A and B are taken to be equal. Take w = 3 kN/m, L1 = 9.6 m, L2 = 3 m and L3 = 6.8 m. L1 L,The 9-k force in Fig. 4-4a is supported by the floor panel DE, which in turn is simply supported at its ends by floor beams. These beams transmit their loads to the simply supported girder AB. Determine the internal shear and moment acting at point C in the girder. 9 k 2 ft t 6 t- 6 ft D 6 ft 15 ft iC 24 ft- (a) Fig. 4-4PROBLEM 1-FIlexure Formula A 200-lb man starts at end A of the wooden plank and walk towards end B. If the plank will fail when the maximum bending stress is 6000 psi, find the farthest distance X that the man can walk safely. 3 Use S=l/c = 1.125 in 144 in Value of reaction at %3D Maximum moment Value of x SOLUTION: II