Answered: In the reactions at 298.15K (1)…

In the reactions at 298.15K (1) C(diamond)+O2(g)-CO2(g) 4,H,=-395.4kJ.mol. (2) C(graphite)=C(diamond) A,H, -1.9 kJ.mol then in the reaction C(graphite)+O2(g)-CO2(g), A,H at 298.15 K is (

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter2: The First Law Of Thermodynamics

Section: Chapter Questions

Problem 2.51E: With regard to exercise 2.50, how accurate do you think your answer is, and why?

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Question

question 5

5.
In the reactions at 298.15K
(1) C(diamond)+O:(g)-CO:(g)
=-395.4kJ.mol",
(2) C(graphite)=c(diamond)
A,H 1.9 kJ.mol-
then in the reaction C(graphite)+02(g)-CO2(g), A,H
at 298.15 K is ( )
A
-1.9 kJ.mol-1
1.9 kJ.mol-1
C
C -395.4 kJ.mol-1
D
-393.5 kJ.mol-1

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