In the following acid-base titration experiment NaOH(aq) + HNO3(aq) ———> NaNO3(aq) + H2O(1). What is the molarity of the HNO3 solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of HNO3? (a) 0.157 M (b) 0.0842 M (c) 3.978 M (d) 0.0157 M

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 37QAP: An artificial fruit beverage contains 12.0 g of tartaric acid, H2C4H4O6, to achieve tartness. It is...
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In the following acid-base titration experiment NaOH(aq) + HNO3(aq) ———> NaNO3(aq) + H2O(1). What is the molarity of the HNO3 solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of HNO3? (a) 0.157 M (b) 0.0842 M (c) 3.978 M (d) 0.0157 M
0.015 moles
0.15 moles
1.5 moles
15 moles
phthalate KHC6H4(CO2)2 is present in 0.1 M, 150 mL solution?
QUESTION 8
In the following acid-base titration experiment
NaOH(aq) + HNO3(aq) ---------> NaNO3(aq) + H₂O(1)
What is the molarity of the HNO3 solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of HNO3?
0.157 M
0.0842 M
3.978 M
0.0157 M
QUESTION 9
In the following acid-base titration experiment
CH3COOH (aq) + NaOH (aq)
What is the molarity of the NaOH solution if 11.6 mL of 3.0 M acetic acid is required to neutralize the sodium hydroxide in 25.00 mL of
0.65 M
6.5 M
96.6 M
1.392 M
-----> CH3COONa (aq) + H₂O (1)
Transcribed Image Text:0.015 moles 0.15 moles 1.5 moles 15 moles phthalate KHC6H4(CO2)2 is present in 0.1 M, 150 mL solution? QUESTION 8 In the following acid-base titration experiment NaOH(aq) + HNO3(aq) ---------> NaNO3(aq) + H₂O(1) What is the molarity of the HNO3 solution if 18.3 mL of 0.115 M NaOH was used to neutralize 25 mL of HNO3? 0.157 M 0.0842 M 3.978 M 0.0157 M QUESTION 9 In the following acid-base titration experiment CH3COOH (aq) + NaOH (aq) What is the molarity of the NaOH solution if 11.6 mL of 3.0 M acetic acid is required to neutralize the sodium hydroxide in 25.00 mL of 0.65 M 6.5 M 96.6 M 1.392 M -----> CH3COONa (aq) + H₂O (1)
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