In the compound K2CrO4 , what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning Oxidation States are given as below) 1) The oxidation numbers of the atoms in a neutral molecule must add up to zero. 2) Group I - +1; Group II – +2; Group III → +3 3) Fluorine - -1 (always) Halogens – -1 (except in compounds with O and other halogens) 4) Hydrogen - +1 (except in metal hydrides, e.g. LiH, Rule 2 and H has - 1) 5) Oxygen - -2 (except in compounds with F, Rule 3) and compounds with O-O bonds (Rules 2 & 4) OA K:+2 , Cr:+2 ,O: -2 OB. K:+1 , Cr:+4 ,0: -2 ocK:+1 , Cr:+2 ,0: -2 O D. K:+2 , Cr:+6 ,0: -2 K:+1 , Cr:+6 ,0: -2 O E.

Chemistry & Chemical Reactivity
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Chapter3: Chemical Reactions
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In the compound K2CrO4, what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning
Oxidation States are given as below)
1) The oxidation numbers of the atoms in a neutral molecule must add up to zero.
2) Group I- +1; Group II → +2; Group III → +3
3) Fluorine - -1 (always)
Halogens --1 (except in compounds with O and other halogens)
4) Hydrogen -
+1 (except in metal hydrides, e.g. LiH, Rule 2 and H has - 1)
5) Oxygen - -2 (except in compounds with F, Rule 3) and compounds with O-O bonds (Rules 2 & 4)
OA K:+2 , Cr:+2 ,0: -2
O B. K:+1 , Cr:+4 ,0: -2
ocK:+1 , Cr:+2 ,O: -2
OD. K:+2 , Cr:+6 ,0: -2
OF K:+1 , Cr:+6 ,0: -2
Transcribed Image Text:In the compound K2CrO4, what is the correct oxidation number of each of its elements? (K is a Group I element) (The rules for assigning Oxidation States are given as below) 1) The oxidation numbers of the atoms in a neutral molecule must add up to zero. 2) Group I- +1; Group II → +2; Group III → +3 3) Fluorine - -1 (always) Halogens --1 (except in compounds with O and other halogens) 4) Hydrogen - +1 (except in metal hydrides, e.g. LiH, Rule 2 and H has - 1) 5) Oxygen - -2 (except in compounds with F, Rule 3) and compounds with O-O bonds (Rules 2 & 4) OA K:+2 , Cr:+2 ,0: -2 O B. K:+1 , Cr:+4 ,0: -2 ocK:+1 , Cr:+2 ,O: -2 OD. K:+2 , Cr:+6 ,0: -2 OF K:+1 , Cr:+6 ,0: -2
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