Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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The oxidation number for As in A s O 4 3 − is BLANK. The oxidation number for oxygen in BaO2 is BLANK . Oxidation number phosphorous in pentaphosphorous pentoxide is BLANK . In this
Numbers only and you must enter (+) or (-) for oxidation numbers.
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- Specify which of the following are oxidation-reduction reactions, and if it is, identify the oxidizing agent, the reducing agent, the substance being oxidized, and the substance being reduced. If it is not, select No and leave the following boxes blank. Express your answers as a chemical formulas. Omit states-of-matter. Zn(s) + 2Ag* (aq) → 2 Ag(s) + Zn2+ * (aq) а. Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced No v b. HBr(g) + NH3 (g) → NH,Br(8) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced Yes v С. GeCl4 (1) + 2H2O(1) → 4HC1(aq) + GeO2 (s) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced d. Si Br4 (1) + 2Ba(s) → 2BAB12 (s) + Si(s) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced Ga(OH), (ag) - → GaO2 (ag) + 2H2O(1) е. Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced Previous Nextarrow_forwardFormation of bromine from bromide. Assign oxidation numbers to each atom. Identify the oxidizing agent and the reducing agent. 2 Br-(aq) + Mn02(s) + 4 H1+(aq)→ Br2(s) + Mn²*(aq) + 2 H20(I)arrow_forwardComplete and balance the following redox equations using the smallest whole-number coefficients. The reaction takes place in a BASIC solution. Fe(OH)2 (s) + MnO4−(aq) → MnO2 (s) + Fe(OH)2 (s) In the balanced equation, 3 OH- are present on the product side. In the balanced equation, 5 molecules of water are present on the reagent side. In the balanced equation, 4 molecules of water are present on the product side. In the balanced equation, 5 molecules of water are present on the product side. In the balanced equation, 3 OH- are present on the reagent side. In the balanced equation, 4 molecules of water are present on the reagent side.arrow_forward
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