In stationary chromatography, the distribution (K) is the main criterion for the division of species in the sample between the two functions of the system, which factors depend on
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- One method for quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is the area normalization method. In this method, complete elution of all of the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction is accomplished by dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2, and 30.2 in the order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78, and 0.88, respectivelyChromatography involves the separation of two or more compounds/ions caused by their molecular interactions with two phases. True FalseOne method for the quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is area normalization. Here, complete elution of all the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction involves dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2 and 30.2, in order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78 and 0.88, respectively.
- You have obtained a gas chromatogram of a two component mixture of compounds A and B. The height of peak A is 3.84 cm. and the width at half height is 1 cm. The height of peak B is 3.49 cm. and the width at half height is 1.36 cm. The percentage of a component in the mixture is proportional to peak area. Estimate peak areas by multiplying height by width at half height. What was the percentage of compound B in the mixture? (Enter your answer as a number without any percent symbol or the word percent.)In centrifugation chromatography (Ka), the main criterion is the division of the species in the sample between the two phases of the poison. *Depending on what factorsThe ages of a group of 122 randomly selected adult females have a standard deviation of 18.5 years Assume that the ages of female statistics students have less variation than ages of females in the general population, so let o = 18 5 years for the sample size caloulation How many female statistics student ages must be obtained in order to estimate the mean age of all female statistics students? Assume that we want 95% confidence that the sample mean is within one-half year of the population mean. Does it seem reasonable to assume that the ages of female statistics students have less variation than ages of females in the general population? The required sample size is (Round up to the nearest whole number as needed)
- (c) Explain how ab initio method is different from semiempirical method.why is it better to generate a calibration plot than to perform a determination using a single measurements for a standard solution?The diffusion coefficient of water molecules in hydrogen (the carrier gas) at 307 k and 1 atm is 1 cm2/sec. What is the average time that the water molecules to travel a distance of 1 mm in the gas chromatographic system? Assuming there no interactions between water and the system.
- 4. A new method for the determination of mercury in fish was tested against a N.I.S.T. standard to determine if there was any bias (determinate error) in the new technique. The N.I.S.T. standard fish sample was certified to contain 13.55 ppm Hg. The results of six analyses by the new method gave a mean value of 14.15 ppm and s.d. = 0.42 ppm. Does the new method give accurate results at the 95% confidence level?1. From spinach, the chromatographic analysis will yield two major substances: (a) B-carotene (C40H56), which will separate from the spinach mixture to form a yellow band, and (b) chlorophyll A (CSSH72MGN4OS), which will separate from the mixture to form a green band. i. Describe the characteristics and draw structures of these molecules. ii. From the spectrophotometric analysis, what wavelength (Amax) would you expect ß-carotene (C40H56) to absorb? What wavelength would chlorophyll A (CssH72MgN4O5) absorb?(a) In High Performance Liquid Chromatography (HPLC), the separation method is by partition of the solute (analyte) between the mobile phase and the stationary phase. Explain how this leads to separation of analyte mixtures; (b) Describe the structure and materials use in a typical column used for HPLC. Thereby explain why high pressures have to be used in HPLC; (c) Discuss how the need for high pressures also imposes requirements on the injector;