In Ocaml Write a function l3_of_3l : ’a list * ’b list * ’c list -> (’a * ’b * ’c) list = that transforms a triple of lists into lists of triples. If lengths don’t match then ignore leftover elements. examples  l3_of_3l ([1;2;3] ,[1.;2.] ,[ ’ a ’; ’b ’; ’c ’; ’d ’]) ;; - : ( int * float * char ) list = [(1 , 1. , ’a ’) ; (2 , 2. ,’b ’) ] l3_of_3l ([1.;2.] ,[ ’ a ’; ’b ’; ’c ’; ’d ’] ,[1;2;3]) ;; - : ( float * char * int ) list = [(1. , ’a ’ , 1) ; (2. , ’b’ , 2) ]

Suppose a node of a doubly linked list is defined as follows:  struct Node{  int data;  struct Node* next;  struct Node* prev;  };  Write the function definition of the function deleteElement as presented below. This function deletes a node at position n from a doubly linked list.  struct Node* deleteElement(struct Node* head, int n){  //write the function definition  }

lst1= [4,3,2,6,2] and lst2=[1,2,4] then the new_list is [2,2,4]. Assign the new-list to variable new_list and sort. Code: What is wrong with this code? lst1= [4,3,2,6,2]  lst2=[1,2,4] new_list=[] for elements1 in lst1:    for elements2 in lst2:        elements1==elements2:        new_list.append(elements1)       new_list.sort()

Write a function called find_duplicates which accepts one list as a parameter.    This function needs to sort through the list passed to it and find values that are duplicated in the list. The duplicated values should be compiled into another list which the function will return. No matter how many times a word is duplicated, it should only be added once to the duplicates list.   NB: Only write the function. Do not call it.   For example: Test Result random_words = ("remember","snakes","nappy","rough","dusty","judicious","brainy","shop","light","straw","quickest", "adventurous","yielding","grandiose","replace","fat","wipe","happy","brainy","shop","light","straw", "quickest","adventurous","yielding","grandiose","motion","gaudy","precede","medical","park","flowers", "noiseless","blade","hanging","whistle","event","slip") print(find_duplicates(sorted(random_words))) ['adventurous', 'brainy', 'grandiose', 'light', 'quickest', 'shop', 'straw', 'yielding']…

3. Write the remove_evens() function that receives a list of integers as a parameter and returns a new list of integers containing only the odd numbers from the original list. Ex1) If n = [1, 2, 3, 4, 5, 6], remove_evens(n) returns [1, 3, 5]. Ex2) If n = [2, 4, 8], remov move_evens(n) returns [].

Pascal triangle! write a function(in OCaml)  val nextpascalrow : int list -> int list = that given a list of integers that correspond to a row of the pascal triangle, it calculates the next row of the pascal triangle. # nextpascalrow [1; 6; 15; 20; 15; 6; 1];; - : int list = [1; 7; 21; 35; 35; 21; 7; 1]

OCAML programming   Pascal triangle Write a function val nextpascalrow : int list -> int list = <fun> that given a list of integers that correspond to a row of the pascal triangle, it calculates the next row of the pascal triangle. # nextpascalrow [1; 6; 15; 20; 15; 6; 1];;- : int list = [1; 7; 21; 35; 35; 21; 7; 1]

Having trouble with creating the InsertAtEnd function in the ItemNode.h file below.  "    // TODO: Define InsertAtEnd() function that inserts a node    //       to the end of the linked list" Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts  ------------------------------------------------------- main.cpp -------------------------------------------------------- #include "ItemNode.h" int main() {    ItemNode *headNode;  // Create intNode objects                                                       ItemNode *currNode;    ItemNode *lastNode;     string item;    int i;    int input;     // Front of nodes list                                                                             headNode = new ItemNode();    lastNode = headNode;     cin >> input;     for (i = 0; i < input; i++) {        cin >> item;…