Complete the function odd_even that classifies an number as either 'odd' or 'even' and the function classify tha takes in a list and applies odd_even to all elements in the list. def odd_even(x): """Classify a number as odd or even. >>> odd_even (4) 'even' >>> odd_even (3) 'odd' |||||| "*** YOUR CODE HERE ***" def classify(s): BEACH Classify all the elements of a sequence as odd or even assify ( [0, 1, 2, 4]) ['even', 'odd', 'even', 'even'] >>> "*** YOUR CODE HERE ***"

Complete the function odd_even that classifies an number as either 'odd' or 'even' and the function classify tha takes in a list and applies odd_even to all elements in the list. def odd_even(x): """Classify a number as odd or even. >>> odd_even (4) 'even' >>> odd_even (3) 'odd' |||||| "* YOUR CODE HERE " def classify(s): BEACH Classify all the elements of a sequence as odd or even assify ( [0, 1, 2, 4]) ['even', 'odd', 'even', 'even'] >>> " YOUR CODE HERE *"

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include <iostream>using namespace std;double median(int *, int);int get_mode(int *, int);int *create_array(int);void getinfo(int *, int);void sort(int [], int);double average(int *, int);int getrange(int *,int);int main(){ int *dyn_array; int students; int mode,i,range;float avrg;do{cout << "How many students will you enter? ";cin >> students;}while ( students <= 0 );dyn_array = create_array( students );getinfo(dyn_array, students);cout<<"\nThe array is:\n";for(i=0;i<students;i++)cout<<"student "<<i+1<<" saw "<<*(dyn_array+i)<<" movies.\n";sort(dyn_array, students);cout << "\nthe median is "<<median(dyn_array, students) << endl;cout << "the average is "<<average(dyn_array, students) << endl;mode = get_mode(dyn_array, students);if (mode == -1)cout << "no mode.\n";elsecout << "The mode is " << mode << endl;cout<<"The range of movies seen is…
1. Write a function named “getSumBeforeNegative” that takes in a pointer to the array of integers and its size. It will return the sum of all values before it sees a negative number. If there is no negative number in the list, it returns the sum of all numbers in the array.For example,int numList[] = {10,20,-1, 30);// will return 30int priceList[] = {10, 20, 30);// will return 60It must use pointers to integer instead of array index.Write a main program and show how this function is called and used.
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#include <iostream> using namespace std; int main(){ int a[100],n,i,item,loc=0; cout<<"Enter number of elements: "; cin>>n; cout<<"\nEnter numbers:\n"; for(i=1;i<=n;i++) { cin>>a[i]; } cout<<"\nEnter number to search:"; cin>>item; for(i=1;i<=n;i++) { if(item==a[i]) { loc=i; break; } } if(loc>0) { cout<<loc<<" is the location of item"; } else cout<<"\nno. not found";} Q: edit the code that shows after how many number of iteration searched value is found
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1.d) In Python, define a function that takes list as a parameter and returns the count of all single-digit numbers in the list.
Question 15 kk .Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line
#include <conio.h>#include <iostream>#include <string> using namespace std;bool check = true;struct node {char name[20];char jobtitle[20];int empno;char branch;node *next;}*head,*lastptr; // pointes void add() // calling {node *p; //*p pomiterp=new node;cout<<"Enter name of employ:"<<endl;gets(p->name);cout<<"Enter job title of employ:"<<endl;gets(p->jobtitle);cout<<"Enter Number of employ:"<<endl;cin>>p->empno;cout<<"Enter branch of employ:"<<endl;cin>>p->branch;p->next=NULL; if(check) //if check is true its means heads is empty and there is no node exist.{head = p;lastptr = p;check = false;}else{lastptr->next=p;lastptr=p;}cout<<endl<<"Recored Entered";} void modify() {node *ptr; node *prev=NULL;node *current=NULL;int e_no;cout<<"Enter Number to…
Data structures must be efficient, reusable, and invisibly invisible. A data structure is a way of organising, managing, and storing data.