Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- T/F 10) We can define a list of int values recursively as: a list_item, followed by a comma, followed by a list where alist_item is any int value.arrow_forward// FILL IN THE BLANKS (LINKED-LISTS CODE) (C++)#include<iostream>using namespace std; struct ________ {int data ;struct node *next; }; node *head = ________;node *createNode() { // allocate a memorynode __________;temp = new node ;return _______ ;} void insertNode(){node *temp, *traverse;int n;cout<< "Enter -1 to end "<<endl;cout<< "Enter the values to be added in list"<<endl;cin>>n; while(n!=-1){temp = createNode(); // allocate memorytemp->data = ________;temp->next = ________;if ( ___________ == NULL){head = _________;} else {traverse = ( );while (traverse->next != ________{traverse = traverse-> ___________;} traverse->next= temp;} cout<<"Enter the value to be added in the list"<<endl;cin>>n; }} void printlist(){node *traverse = head; // if head == NULLwhile (traverse != NULL) { cout<<traverse->data<<" ";traverse = traverse->next;}} int main(){int option; do{cout<<"\n =============== MAIN…arrow_forwardC++ Data Structure:Create an AVL Tree C++ class that works similarly to std::map, but does NOT use std::map. In the PRIVATE section, any members or methods may be modified in any way. Standard pointers or unique pointers may be used.** MUST use given Template below: #ifndef avltree_h#define avltree_h #include <memory> template <typename Key, typename Value=Key> class AVL_Tree { public: classNode { private: Key k; Value v; int bf; //balace factor std::unique_ptr<Node> left_, right_; Node(const Key& key) : k(key), bf(0) {} Node(const Key& key, const Value& value) : k(key), v(value), bf(0) {} public: Node *left() { return left_.get(); } Node *right() { return right_.get(); } const Key& key() const { return k; } const Value& value() const { return v; } const int balance_factor() const {…arrow_forward
- #include <iostream> #include <string> #include <cstdlib> using namespace std; template<class T> class A { public: T func(T a, T b){ return a/b; } }; int main(int argc, char const *argv[]) { A <float>a1; cout<<a1.func(3,2)<<endl; cout<<a1.func(3.0,2.0)<<endl; return 0; } Give output for this code.arrow_forwardC++ Given code #include <iostream>using namespace std; class Node {public:int data;Node *pNext;}; void displayNumberValues( Node *pHead){while( pHead != NULL) {cout << pHead->data << " ";pHead = pHead->pNext;}cout << endl;} //Option 1: Search the list// TODO: complete the function below to search for a given value in linked lsit// return true if value exists in the list, return false otherwise. ?? linkedlistSearch( ???){ } //Option 2: get sum of all values// TODO: complete the function below to return the sum of all elements in the linked list. ??? getSumOfAllNumbers( ???){ } int main(){int userInput;Node *pHead = NULL;Node *pTemp;cout<<"Enter list numbers separated by space, followed by -1: "; cin >> userInput;// Keep looping until end of input flag of -1 is givenwhile( userInput != -1) {// Store this number on the listpTemp = new Node;pTemp->data = userInput;pTemp->pNext = pHead;pHead = pTemp;cin >> userInput;}cout <<"…arrow_forwardQuestion 15 kk .Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this linearrow_forward
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- ] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Pythonarrow_forwardQ1: Assignment Difficulty Dan has a list of problems suitable for Assignment 4. The difficulties of these problems are stored in a list of integers . The problem’s difficulty is represented by (the higher the integer, the more difficult the problem).ai-tha[i] Dan is too busy eating saltines to worry about Assignment 4 decisions, so he asks Michael the TA to select at least two problems from the list for the assignment. Since there are many possible subsets of the problems to consider and Michael has a life, he decides to consider only sublists (definition follows) of the list of problems. To make grading the assignment easier, Michael wants to pick problems that don’t vary too much in difficulty. What is the smallest difference between the difficulties of the most difficult selected problem and the least difficult selected problem he can achieve by selecting a sublist of length at least 2 of the original list of problems? Definition: A sublist of a list is any list you can obtain by…arrow_forwardT/F 25) If a is an ArrayList, we can say a.add(5); to add an integer to a.arrow_forward
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