In lectures the Lagrangian approach was applied to a mass (m) sliding down a wedge (M) that was sitting on a horizontal surface, with no friction between any surfaces. The generalised co-ordinates used in the analysis were the horizontal position of the wedge (x), and the position of the mass along the slope of the wedge as measured down from the top of the wedge (x'). The Lagrangian could be written L = M² + m (ï¹² + ï² + 2ï' ï cos 0) + mgx' sin What would be the Lagrangian for this system if the the x' generalised co-ordinate measured the horizontal position of the mass m? O The Lagrangian would be unchanged. ○ L = ¼/Mx² + ½ m (x¹² + x²) +mgx' O None of these; in this case and x' do not meet the conditions for generalised co-ordinates of the system. OL= ² + (x² – x¹² – 2ïï¹) mge tan 6

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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In lectures the Lagrangian approach was applied to a mass (m) sliding down a wedge (M) that was sitting on a horizontal
surface, with no friction between any surfaces.
The generalised co-ordinates used in the analysis were the horizontal position of the wedge (x), and the position of the
mass along the slope of the wedge as measured down from the top of the wedge (x').
The Lagrangian could be written L =
M² + m (ï¹² + x² + 2ï'ï cos 0) + mgx' sin
What would be the Lagrangian for this system if the the x' generalised co-ordinate measured the horizontal position of the
mass m?
O The Lagrangian would be unchanged.
OL= = ²/ Mi² + ¼½ m (x²¹² + x²) +mgx'
O None of these; in this case x and a' do not meet the conditions for generalised co-ordinates of the system.
○ L = M² + ¹² (x² – †¹² — 2ïï¹) mge tang
Transcribed Image Text:In lectures the Lagrangian approach was applied to a mass (m) sliding down a wedge (M) that was sitting on a horizontal surface, with no friction between any surfaces. The generalised co-ordinates used in the analysis were the horizontal position of the wedge (x), and the position of the mass along the slope of the wedge as measured down from the top of the wedge (x'). The Lagrangian could be written L = M² + m (ï¹² + x² + 2ï'ï cos 0) + mgx' sin What would be the Lagrangian for this system if the the x' generalised co-ordinate measured the horizontal position of the mass m? O The Lagrangian would be unchanged. OL= = ²/ Mi² + ¼½ m (x²¹² + x²) +mgx' O None of these; in this case x and a' do not meet the conditions for generalised co-ordinates of the system. ○ L = M² + ¹² (x² – †¹² — 2ïï¹) mge tang
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