In Einstein's photoelectric experiment, the kinetic energy (K.E.) of an electron displaced from a metal by a photon was the difference in energy between the photon and a threshold energy value for the metal. If you were to perform a similar experiment with the metal platinum, which has a threshold energy of 9.04 × 10⁻¹⁹ J, and ultraviolet light of wavelength 45.5 nm, what would be the speed (v) of the dislodged electron in meters per second? (K.E. = 1/2mv². The mass of the electron = 9.109 × 10⁻³¹ kg.)
In Einstein's photoelectric experiment, the kinetic energy (K.E.) of an electron displaced from a metal by a photon was the difference in energy between the photon and a threshold energy value for the metal. If you were to perform a similar experiment with the metal platinum, which has a threshold energy of 9.04 × 10⁻¹⁹ J, and ultraviolet light of wavelength 45.5 nm, what would be the speed (v) of the dislodged electron in meters per second? (K.E. = 1/2mv². The mass of the electron = 9.109 × 10⁻³¹ kg.)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In Einstein's photoelectric experiment, the kinetic energy (K.E.) of an electron displaced from a metal by a photon was the difference in energy between the photon and a threshold energy value for the metal. If you were to perform a similar experiment with the metal platinum, which has a threshold energy of 9.04 × 10⁻¹⁹ J, and ultraviolet light of wavelength 45.5 nm, what would be the speed (v) of the dislodged electron in meters per second? (K.E. = 1/2mv². The mass of the electron = 9.109 × 10⁻³¹ kg.)
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