In each row, pick the compound with the bigger lattice energy. Note: lattice energy is always greater than zero. Which compound has the bigger lattice energy? Nal Na Cl O Rb Br CaO o X Sr Br₂ CaF₂ 5

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Predicting the relative lattice energy of binary ionic compounds In each row, pick the compound with the bigger lattice energy. Note: lattice energy is always greater than zero. Which compound has the bigger lattice energy? BaCh BaS Bel₂ KF O BeBr₂ CsF O 1/5

Cyanamide is a compound containing two hydrogen atoms and some amount of C and N. There are a total of 5 atoms in the compound. The products of combustion were found to be CO2, NO2, and H2O. If the enthalpy of combustion for cyanamide is – 671.9 kJ/mol and the enthalpy of formation is 58.8 kJ/mol, what is the chemical formula for cyanamide? ( ΔfH (CO2) = - 393.51 kJ/mole; ΔfH (NO2) = + 33.10 kJ/mole; ΔfH (H2O) = - 241.826 kJ/mole)

Identify the compound with the highest magnitude of lattice energy.   NaF   KF   LiF   CsF

Say which atom is the C and the O is bonded with for reactants and products

need help with the lattice energy

Given the following bond energies F-F 157 kJ/mol Cl-CI 243 kJ/mol F-CI 193 kJ/mol estimate AH for this reaction. F2(g) + Cl2(g) → 2CIF(g)

Suppose a chemist discovers a new metallic element and names it "Xercisium" (Xr). Xr exhibits chemical behaviour similar to an alkaline earth. Xr(s) + Cl2(g) → XrCl2(s)   Lattice energy for XrCl2 -2020. kJ/mol First Ionization energy of Xr  500. kJ/mol Second Ionization energy of Xr  950. kJ/mol Electron affinity of Cl -348.7 kJ/mol Bond energy of Cl2  239 kJ/mol Enthalpy of sublimation (atomization) of Xr      200. kJ/mol Use the above data to calculate ΔH°f for Xercisium chloride.

As seen in the table, compounds containing an integer ratio of elements depend on how many cations combine with how many anions to form a stable compound. For example, in table 1, to form a NaCl compound, first Na ionizes from the Na+ cation which is having +1 positive charge, which will lose 1 electron, it is having +1 charge, this electron then goes to Cl and it will change to Cl- anion by gaining the electron, so here 1:1 ratio charge which means 1 Na+ combines with 1 Cl-1 to form NaCl. So here integer ratio is 1:1 for this sodium chloride compound. As listed in table 2, Mg(OH)2, the integer ratio is 1:2 which means, Mg is a neutral atom that loses 2 electrons and forms an Mg+2 cation, which combines with OH which gains 1 electron to form OH- anion, So here Mg2+ can combine with 2 OH- anion,  so they both combine to form Mg(OH)2 which has integer ratio as 1:2 . Thus, atom forms as ions by losing or gaining electrons and combines together in whole number ratio to form stable…