Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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In an experiment focusing on weight gain between ages 3 and 6 weeks in mice, the difference in mean
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- Last summer you were walking in the woods when you stumbled upon a group of four tiny baby squirrels. You noticed that they all had different tail lengths. Curious, you decided to measure the tail lengths of the four squirrels. Their tail lengths were found to be: 30 mm, 38 mm, 32 mm, and 28 mm. The heritability for tails in squirrels is 0.33. (This is a fraction, not percent.) What is the variance due to the difference in environment (VE)? Round to two decimals and do not include units.arrow_forwardPopulation A consists of 100 hens that are fully isogenicand that are reared in a uniform environment. Theaverage weight of the eggs they lay is 52 g, and the variance is 3.5 g2. Population B consists of 100 geneticallyvariable hens that produce eggs with a mean weight of52 g and a variance of 21.0 g2. Population B is raised in anenvironment that is equivalent to that of Population A.What is the environmental variance (Ve) for egg weight?What is the genetic variance in Population B? What is thebroad-sense heritability in Population B?arrow_forwardConsider the following three point trihybrid testcross ibvolving traits in dragons. The genotypes determining the 8 progeny types from this testxross are shown below out of a sample of 1572 flies. What number of progeny for each genotype would you predict in the case of independent assortment. gametes number K L M 621 klm 608 k L M 103 K lm 109 K lm 64 k L m 57 K L m 3 k l M 7arrow_forward
- A complementation analysis was performed using pea plants which normally have purple flowers. Twenty-five mutants for white flower colour were discovered across 10 populations. The mutants were bred in a complementation test which showed two complementation groups with 10 mutants in one group and 15 in the other. (a) How many genes contribute to flower colour in pea plants based on this data? (b) Is it likely that more genes contribute to pea plant flower colour? Explainarrow_forwardPretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…arrow_forwardOne variety of pigs reach maturity at 81 days with a variance of 6.4 days2 while a second variety takes 93 days to reach maturity with a variance of 6.6 days. An F2 population derived from these populations takes 87 days to reach maturity and has a variance of 8.5 days. What is the broad-sense heritability for this trait?arrow_forward
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