In acidic solution, Li2CO3 is fully soluble. Dissolving 3.90 g of Li2CO3 in 50.0 mL of acidic solution causes the temperature of the water to decrease from 20.00 to 16.79 °C. Assume that the specific heat of the solution equals 4.184 Jg-1K-1. Consider the mass of the salt to be negligible, and ignore any heat generated by acid-base chemistry. Find the molar enthalpy of dissolution for the salt under these conditions. In neutral solution, the Ksp of Li2CO3 is 2.50 x 10-2. What is the temperature change when placing the same mass of Li2CO3 in 50.0 mL of pure water, in °C? Question 1 options: -0.56 -0.028 -0.067 -0.80 -0.15

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
Author:Skoog
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Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.1QAP
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In acidic solution, Li2CO3 is fully soluble. Dissolving 3.90 g of Li2CO3 in 50.0 mL of acidic solution causes
the temperature of the water to decrease from 20.00 to 16.79 °C. Assume that the specific heat of the
solution equals 4.184 Jg-1K-1. Consider the mass of the salt to be negligible, and ignore any heat generated
by acid-base chemistry. Find the molar enthalpy of dissolution for the salt under these conditions. In neutral
solution, the Ksp of Li2CO3 is 2.50 x 10-2. What is the temperature change when placing the same mass of
Li2CO3 in 50.0 mL of pure water, in °C? Question 1 options: -0.56 -0.028 -0.067 -0.80 -0.15
Transcribed Image Text:In acidic solution, Li2CO3 is fully soluble. Dissolving 3.90 g of Li2CO3 in 50.0 mL of acidic solution causes the temperature of the water to decrease from 20.00 to 16.79 °C. Assume that the specific heat of the solution equals 4.184 Jg-1K-1. Consider the mass of the salt to be negligible, and ignore any heat generated by acid-base chemistry. Find the molar enthalpy of dissolution for the salt under these conditions. In neutral solution, the Ksp of Li2CO3 is 2.50 x 10-2. What is the temperature change when placing the same mass of Li2CO3 in 50.0 mL of pure water, in °C? Question 1 options: -0.56 -0.028 -0.067 -0.80 -0.15
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