
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![Liquid ammonia (anhydrous NH3(0)) is often used as a solvent. Like water, ammonia undergoes autoionization by the transfer of a proton:
2NH3 = NH4+ + NH2"
K = 1x10-33 at -50°C
Since ammonia is better proton acceptor than water, the ionization of acids is relatively enhanced in liquid ammonia. For example, acetic acid is a strong acid in liquid ammonia.
Estimate [NH4+] (mol/L) in pure (i.e. neutral) liquid ammonia at -50°C.
mol/L
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Calculate [NH4+] (mol/L) in a 7.07x10-5 M solution of acetic acid in liquid ammonia at -50°C.
mol/L
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Estimate [NH2] (mol/L) in a 7.07x10-5 M solution of acetic acid in liquid ammonia at -50°C.](https://content.bartleby.com/qna-images/question/14f6f234-105d-4046-a76a-a0e18732da07/a4665f04-8c70-4224-a5b3-3bfc22e96185/b1lsh1q_thumbnail.jpeg)
Transcribed Image Text:Liquid ammonia (anhydrous NH3(0)) is often used as a solvent. Like water, ammonia undergoes autoionization by the transfer of a proton:
2NH3 = NH4+ + NH2"
K = 1x10-33 at -50°C
Since ammonia is better proton acceptor than water, the ionization of acids is relatively enhanced in liquid ammonia. For example, acetic acid is a strong acid in liquid ammonia.
Estimate [NH4+] (mol/L) in pure (i.e. neutral) liquid ammonia at -50°C.
mol/L
Submit Answer
Tries 0/5
Calculate [NH4+] (mol/L) in a 7.07x10-5 M solution of acetic acid in liquid ammonia at -50°C.
mol/L
Submit Answer
Tries 0/5
Estimate [NH2] (mol/L) in a 7.07x10-5 M solution of acetic acid in liquid ammonia at -50°C.
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