In a single-slit diffraction experiment, the slit width is 0.185 mm and the wavelength of the light used is 576 nm. (a) Find the angle of a line from the center of the slit to the first dark fringe. (b) You might expect the intensity at one-half the angle found in part (a), which is halfway between the middle of the central bright fringe (where the intensity is I0) and the first dark fringe (where the intensity is zero), to be I0/2. What is the actual intensity at this angle?

Light of wavelength 588.2 nm illuminates a slit of width 0.63 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.86 mm from the central maximum? (b) Calculate the width of the central maximum. Step 1 (a) As shown in the figure, dark bands or minima occur where sin 0 = m(2/a). For the first minimum, m = 1 and the distance from the center of the central maximum to the first minimum is y₁ = L tan 8, where L is the distance of the viewing screen from the slit. 32 sin dark = 22/a 31 sin dark = λ/a HE 0 -1 sin dark = -λ/a -2 sin dark = -22/a Viewing screen a Because is very small, we can use the approximation tan sin 0 = m(2/a). Substituting the approximation and solving for the distance to the screen, we have 6.3 x 10 m ³ m ) (₁ L = = y ₁ ( ² ) = x 10-3 m x 10-⁹ m m.

Coherent electromagnetic waves with wavelength l = 500 nm pass through two identical slits. The width of each slit is a, and the distance between the centers of the slits is d = 9.00 mm. (a) What is the smallest possible width a of the slits if the m = 3 maximum in the interference pattern is not present? (b) What is the next larger value of the slit width for which the m = 3 maximum is absent?

In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright fringe on a flat screen is 0.0169 m, when the light has a wavelength of 425 nm. Assume that the angles are small enough so that sin (0) is approximately equal to tan (0). Find the separation y when the light has a wavelength of 584 nm. Number i Units ✪

The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of a Its) Hepre T thickness t and refractive index u is put in front of one of the slits, the a(μµ − 1) - central maximum gets shifted by a distance equal to n fringe widths. If the wavelength of light used is λ, t will be 2nDλ (a) (b) 2Dλ a(μ-1) (c) Dλ a(µ − 1) - D (d) Screen nDλ a(μµ - 1)

In a diffraction experiment the 1st order light (m = 1) from a diffraction grating  is falling onto a single slit (see picture below). The light from the slit is then observed on a second screen and the measured width of the central diffraction peak is found to be 8 mm. Calculate the number of lines per millimetres of the grating. The distance from the slit to the second screen is 1.37 m, the distance from the diffraction grating to the screen with the slit is 5 m, the slit width is 0.25 mm and the distance from the middle of the screen with the slit to the slit is 10 mm..

In a Young's double slit experiment the slit separation is 0.4 mm and the distance between the screen and the slit is 120 cm. If the 3rd dark fringe formed at 0.5 cm from the central bright fringe. Find the wavelength of the light in cm. (a) 6.6x10- cm (b) 3.3×10- cm (c) 4.5x10 cm (d) 5.5x103 cm

In a Young's double-slit experiment, a set of parallel slits with a separation of 0.108 mm is illuminated by light having a wavelength of 584 nm and the interference pattern observed on a screen 3.50 m from the slits. (a) What is the difference in path lengths from the two slits to the location of a third order bright fringe on the screen? answer in ?m (b) What is the difference in path lengths from the two slits to the location of the third dark fringe on the screen, away from the center of the pattern? answer in ?m

Problem 7:   Consider light falling on a single slit, of width 1.05 μm, that produces its first minimum at an angle of 33.6°.Randomized Variables θ = 33.6°w = 1.05 μm   Calculate the wavelength of the light in nanometers.

Problem 2: Consider light that has its third minimum at an angle of 23.6° when it falls on a single slit of width 3.55 μm. Randomized Variables 9 = 23.6° w = 3.55 um D Find the wavelength of the light in nanometers. λ=1 sin() cos() cotan() asin() atan() acotan() tanh() cosh() O Degrees Hints: 2% deduction per hint. Hints remaining: 2 Submit tan() JU acos() E sinh() cotanh() Radians Hint ( + 7 8 9 4 5 6 1 0 VO BACKSPACE Feedback 2 3 All content © 2022 Expert TA, LLC DEL HOME END I give up! Feedback: 2% deduction per feedback. CLEAR