Calculate the maximum diffraction order observed on a screen in a two slit interference experiment (see picture below) considering that the distance between two slits is 3.8 mm, the distance to the screen is 2 m. The slits are illuminated by the light with 500 nm wavelength and the size of the screen is 1 m. Slits 1 Answer: 0.5m 1m

In the process of performing an analysis, you determine that you need to improve the precision by limiting the error in the absorbance to 9.400 x 10%. You attempt to achieve this by reducing the amount of stray light that reaches the detector. What is the maximum amount of stray light that can reach the detector that will limit the error in the absorbance to 9.400 x 10 for a true absorbance of 1.0000000? s= 222 x10-5 Incorrect

Babinet's principle says that the diffraction pattern observed when light falls on an aperture of any shape is the same as that obtained when light falls on an object that is the complement of such aperture. A laser with a wavelength of 600 nm is incident on a hair, generating a diffraction pattern with a width of the principal maximum of 10 mm on a screen located 1 m away from the hair. What is the diameter of this wire?

The single slit experiment was carried out using light having a wavelength of 500 nm, perpendicular to the 5 µm wide slit. The distance between the screen and the gap is 3.5 m. Calculate the distance between the center diffraction pattern and the minimum second diffraction

A diffraction grating is placed in front of a laser beam, resulting in various bright spots appearing on a screen. Given the following values, and the positions of the dots on the screen (in metres), find the number of grating lines per mm.

In an interference experiment using a monochromatic source emitting light of wavelength 1, the fringes are produced by two long, narrow slits separated by a distance d. The fringes are formed on a screen which is situated at a distance D >> d.Write down an expression for the fringe width w. Please use "*" for products (e.g. B*A), "/" for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. Use "lambda" (without the quotes) for 1 in the equation box. For example, use d*lambda for d2. Please use the "Display response" button to check you entered the answer you expect. w=

You measure three segments of the distance between a diffraction slit an the screen on which the pattern forms: x1 = (15.8 ± 0.2) cm, x2 = (6.7 ± 0.1) cm, and x3 = (11.3 ± 0.1). What is the uncertainty of the total distance x1 + x2 + x3? Group of answer choices 0.4 cm 0.5 cm 0.2 cm 0.3 cm 0.1 cm

air 1. n = 1 [a] The figure shows a soap film of thickness dį in air. Light impinges on the film with an angle of incidence 01 and is reflected and refracted at the interfaces. Rays 1 and 2 represents reflected light, while rays 3 and 4 represent light that has been transmitted into the glass. soap \[c] n, = 1.33 |d [b] air n= 1 3 4 The bracketed letters (a], [b], and [c] indicate reflections at the air-soap, and soap-air interfaces. For which of these reflections does a phase change of n occur? Check all that apply. [a] [b] O (c)

The full width at half-maximum (FWHM) of a central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (See figure (b).) (a) Does the intensity drop to one-half the maximum value when sin²α = a²/2? (b) Is a = 1.39 rad (about 80°) a solution to the transcendental equation of (a)? (c) Is the FWHM AÐ = 2sin¹(0.442 A/a), where a is the slit width? Calculate the FWHM of the central maximum for slit width (d) 1.17 A, (e) 5.03 A, and (f) 11.7 A. 20 20 Relative intensity 15 10 0.8 0.6 a=2 0.4 0.2 5 05 8 (degrees) (a) 10 15 20 20 Relative intensity 1.0 0.8 0.6 -A0- 0.4 0.2 a= 52 20 15 10 5 0 5 10 15 20 (degrees) (b)

In a Young's double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe is 4.0 degrees. Find the ratio d/A of the slit separation d to the wavelength of the light. Number Units