IN A SERIES RLC CIRCUIT DRIVEN BY SINUSOIDAL INPUT SIGNAL, THE PHASE BETWEEN THE CURRENT AND THE INPUT VOLTAGE IS PLOTTED IN THE NEXT GRAPH. When the frequency f= = 60 kHz the phase (in radians) between the voltage on the capacitor and the voltage on the inductor is about: 1.6
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- Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 9.35 Volts and is running at a frequency of f = 113000 Hz. The resistor has a resistance of R = 1980 , the capacitor has a capacitance of C = 1.08e-09 Farads, and the inductor has an inductance of L = 3.71e-03 Henries. mm Vps Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit øztot Determine the numerical value of Ztot = 2384 Determine the numerical value of @Z tot Determine the current through the circuit: ● R www I(PEAK) = I(RMS) = ● ● Determine the voltage across the inductor: • VL(PEAK) = Volts Volts VL(RMS) = Amps Amps Determine the voltage across the capacitor: Vc(PEAK) = Volts Volts Vc(RMS) = = 33.85 a capacitive switcher Ω degrees C If a second circuit were connected in parallel with the resistor, this circuit would be considered as: O a high-pass filter a radio tuner O…C. Convert (6-j8) to polar form, exponential form and trigonometric form.Problem 6: w- Calculate the voltage across the capacitor every 15 0.1 ms for one complete period of the input waveform. Then, use Multisim to sketch the 25 V (n capacitor waveform. Repeat the calculation and the simulation for a frequency of 2 kHz
- A 10.0-μF capacitor and a 2.00-H inductor are connected in series with a 60.0-Hz source whose rms output is 100 V. Finda. the rms current in the circuit.b. the voltage drop across the inductor. c. the voltage drop across the capacitor.A capacitor in series with a 200 ohms resistor draws a current of 0.3 ampere from 120 volts, 60 hz source. What is the value of the capacitor in microfarad? a. 8.7 b. 9.7 c. 6.7 d. 7.7Please explain this question properly A capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage
- C5 What is the correct explanation for the voltage seen at Va in Figure C5? Va 1 Sost We will assume that the Vout Out Vb, capacitor is charged to a value determined by the feedback and the supply voltage +BVsat. Figure C5 A. The waveform on the capacitor looks like a discharge, and then a charging waveform to an equal but opposite magnitude voltage, B. The capacitor simply reverses its charge, with a charging waveform, C. The capacitor simply reverses its charge, with a discharging waveform, D. None of the above.Describe the resulting waveforms when the capacitors (initially 20uF and then replaced with 100uF) were connected in parallel with the loadA capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage
- 4. Find Idc, Vdc and the capacitance that will force the Vr(pp) to 2mV. Draw the output waveform across the capacitor. Fin=60HZ. TX1 D1 Ge Vac Lst 230V Lp 1 RL 12-0-12 Center tapped CL 1k D2 Ge 2Answer the following with illustration and solution. 1.) A circuit consisting of a resistor of 5kohms in series with a capacitor of 10 nanofarad is connected across a 16v sinusoidal supply. Calculate the output voltage at a frequency of 60Hz and again at frequency of 120Hz. This is the example/guide that might help.Show the Analog Waveform Signal of the problem below. Please include the formula you will be using to get the waveform, also include what application you will be using to get the waveform. If you will use sine or cosine, please include the whole formula so I could just substitute it from the problem below. Problem: An oscilloscope's output is an analog signal that ranges only from 12.5mV to 50mV, while its highest frequency is 50kHz.