Illustrate a typical stress-strain curve for brittle and ductile materials.

Q2c) Listed in the table below is the tensile stress-strain data for different grades of steels. Utilizing the data given answer the three queries given below. Material Yield Tensile Strain at Fracture Elastic StrengthStrengthFractureStrengthModulus (MPa) (MPa) (MPa) (GPa) A 410 1440 0.63 265 410 В 200 220 0.40 105 250 C 815 950 0.25 500 610 D 800 650 0.14 720 210 E Fractures before yielding 650 550 1) Which will experience the greatest percent reduction in area? Why? 2) Which is the strongest? Why? 3) Which is the stiffest? Why?

Discuss the concept of strain hardening in materials?

The stress-strain curve for mild steel is shown in figure given below. Choose the correct option referring to both figure and table. R Q. R. S. T. U. S U Point on the graph Description of the point P. 1. Upper yield point 2. Ultimate tensile strength 3. Proportionality limit 4. Elastic limit 5. Lower yield point 6. Failure

Draw the stress-strain diagram for any ductile and brittle material and explain the following points: (a) Modulus of elasticity (b) Yield strength (c) Ultimate Strength (d) Ductility (e) Toughness

Describe the Plane Strain and Axisymmetrical Strain.

An elastoplastic material with strain hardening has the stress–strain relationship shown in Figure 1.6(c). The modulus of elasticity is 175 GPa, yield strength is 480 MPa, and the slope of the strain-hardening portion of the stress–strain diagramis 20.7 GPa.a. Calculate the strain that corresponds to a stress of 550 MPa.b. If the 550-MPa stress is removed, calculate the permanent strain.