Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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- Consider the three single-phase two-winding transformers shown in Figure 3.37. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in , place the polarity marks, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a, b, and c such that VAN is 90 out of phase with Va for positive sequence.arrow_forwardFigure below shows a power system. The rating of generators and transformers are:G1:25MVA, 6.6KV, jO.2 p.u. G2:15MVA, 6.6KV, jo.15 p.u. G3:30MVA, 13.2KV, jo.15 p.u. T1: 30MVA, 6.6A- 115Y KV, jo.1 p.u.T2: 15MVA, 6.6A- 115Y KV, jo.1 p.u. T3:single phase units each rated 10MVA, 69/ 6.9 KV, jo.1 p.u. Find te reactances in p.u, take a base of 30MVA, 6.6 KV in the circuit of G1 .=.XG1 G2} 4 A lubu T2 T1 T3 G1 G3 j120 2 j90 Narrow_forward2) The power system consists of generators, motors, transformers, and transmission lines. The ratings are as follows: G1: 3-phase generator 25 MVA, 11 KV, X = 20% M1: 3-phase motor M2: 3-phase motor T1:3 single phase transformers T2: 3-phase transformer Line: 15 MVA, 13 KV, X = 25% 7.5 MVA, 13 KV, X = 25% Single phase transformer rating 30 MVA, 6.9/69 KV X = 10% Three phase transformer rating 30 MVA, 13.8/69 KV X = 10% Χ - 50 Ω = Τι G₁ 2. Line Figure 1. 3 T2 Σ M₁ Δι M2 Find the reactance (X) in p.u. units, given the base value of 25 MVA, 11 KV.arrow_forward
- 1. A single-phase power system as shown in Figure 1 consists of a 240 V, 60 Hz generator supplying a load, Zod = 8 + j6 Q through a transmission line of impedance, Zne = 0.08 + j0.14 Q. Answer the following questions: (1) transformer, T; and T2. Determine the voltage at the load and transmission line losses without the (ii) Determine the voltage at the load and transmission line losses with the transformer, T, and T2. T1 T2 1:10 10:1 IG Zaine Zioad source Figure 1arrow_forwardEquipment ratings and per-unit reactances for the system shown in the below figure are given as follows: Synchronous generators: GI 100 MVA 25 kV X1 = X2 = 0.2 Xo = 0.05 G2 100 MVA 13.8 kV X = X2 = 0.2 Xo =0.05 Transformers: TI 100 MVA 25/230 kV X = X2 = X, = 0.05 T2 100 MVA 13.8/230 kV X = X2 = Xo = 0.05 Transmission lines: TL12 100 MVA 230 kV X = X2 = 0.1 Xo =0.3 TL13 100 MVA 230 kV X = X2 = 0.1 Xo = 0.3 %3D TL23 100 MVA 230 kV X = X2 = 0.1 Xo = 0.3 %3D Using a 100-MVA, 230-kV base for the transmission lines, draw the per-unit sequene networks and reduce them to their Thévenin equivalents, “looking in" at bus 3. Neglect A-Y phase shifts. Compute the fault currents for a bolted three-phase fault at bus 3. 2 T2 b T1 TL12 to G1 G2 TL13 TL23 j0,03 j0,03 3arrow_forwardOne-line diagram of a power system is shown below. Relevant details are mentioned below. Generator: 100 MVA, 11 kV, 3-phase, reactance 20%; Transformer T1: 100 MVA, 10/132 kV, reactance 6%; Transformer T2: 80 MVA, 132/10 kV, reactance 5%; Line reactance is 100 Q. Motors M1 and M2 are rated at 50 MVA and 40 MVA respectively both at 10 kV and 20% reactance. In the above, reactances are per-phase values. Taking generator rating as base, draw the per- phase impedance diagram in which the elements need to be expressed in per unit. * T1 M, Transmission Line G M2) Aarrow_forward
- Problem 1 - Series en Parallel AC networks [19] Look at the circuit in Figure 1 and determine the following: (a) Total Admittance. (b) Total Impedance. (c) Total Current (l:). (d) Current (I1) through impedance Z2. (e) Current (12) through impedance Z3. (f) Current (I3) through impedance Z4. (g) Is this an inductive or capacitive circuit? A. B Zs 220V;50HZ Figure 1 (h) Voltage across Z1. (i) Voltage across A and B. G) Voltage across Zs. Z1 = 3 + j5 ohm Z2 = 10 + jo ohm Z3 = 5 + j15 ohm Z4 = 10 – j30 ohm Zs = 20 – j30 ohm Admittance and Impedance in rectangular notation. All currents and voltage in polar notation. Take voltage as reference.arrow_forwardb) Two synchronous generators, G2 and G2, are connected parallelly supplying a load. Generator G1 has a no-load frequency of 50.5 Hz and a slope of 300 MW/Hz. Generator G2 has a no-load frequency of 50.2 Hz and a slope of 500 MW/Hz. The load consumes 250 MW real power. (1) At what frequency does this system operate, and how much power is supplied by each of the two generators? (ii) An additional 100 MW load is added to this power system. What is the new system frequency, and how much power do G1 and G2 supply? (iii) The governor set point of G2 is changed to control system frequency back to 50 Hz. Determine the G2 governor set point.arrow_forwardQ2\ Two generators G1 & G2 are rated 15 MVA, 11 kV and 10 MVA, 11 kV respectively. The generators are connected to a transformer as shown in the following figure. Find the sub- transient current in each generator when a three-phase fault occurs on the high voltage side of the transformer. A/Y 15 MVA, 11 kV, X"gl=j0.10 pu G2 15 MVA, 11/66 kV, Xr-j0.06 pu 10 MVA, 11 kV, X"g2-j0.10 puarrow_forward
- Assume a transformer rated 700 MVA with 145 kV on the secondary side. Determine the base current and base impedance. For the one line diagram shown, determine the pu reactances and draw the reactance diagram choosing 100 MVA and 20 kV as base values for generator. T1 T2 1 Vm Line G M G1- 60 MVA, 20 kV, X= 9% T1- 50 MVA, 20/200 kV, X =10% T2- 50 MVA-200/20 kV, X=10% М-43.2 MVA, 18 kV, X-8% Line- 200 kV, Z= 120+j200 ohms. 2.arrow_forwardPlease, I do not want a theoretical solution or using artificial intelligence. I want a solution on paper using the mathematical laws of the topicarrow_forward2.2 Three 20 MVA, 11/0.66 kV, 50 Hz, 3-phase transformers are connected together to supply a mining load. State the main conditions necessary before these three transformers are connected together. (4) nit%202%20Thre....pdf A Unit%202%20Thre....pdf A Unit%201%20-%2.pdf 40) Show al 9:12 AM 7/24/2021arrow_forward
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- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning
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ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:Cengage Learning