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- Iterative FactorialWrite an iterative version (using a loop instead of recursion) of the factorial functionshown in this chapter. Test it with a driver program.Task 4: The first problem that you solve recursively is to implement enoughGate() to check if the dogMaze has at least two gates (one for the entrance and one for the exit). This problem must be solved recursively, however there is no limitation on what type of recursion (i.e., direct or indirect recursion) you use . As a reminder, a direct recursion refers to the function that calls itself to solve the given problem. However, by indirect recursion, more than one function involves in solving the problem. It is possible that a non-recursive function solves a small part of the problem and then calls the recursive function to finish the job. /** * This method returns true if the number of * gates in dogMaze >= 2. * @return it returns true, if enough gate exists (at least 2), otherwise false. */ publicboolean enoughGate (){ // insert your code here. Change the return value to fit your purpose. return true; }write a recursive version. The function takes two string parameters, s1 and s2 and returns the starting index of s2 inside the first string s1, or -1 if s2 is not found in s1. You must not use any loops; you also cannot use the string member functions find or rfind. You may use the member functions size, at and substr. Your function must be recursive. CANNOT MODIFY GRAY AREA
- Create a recursive find method that returns a Teacher if it's found or null if it's not found.write a recursive version. The function takes two string parameters, s1 and s2 and returns the starting index of s2 inside the first string s1, or -1 if s2 is not found in s1. You must not use any loops; you also cannot use the string member functions find or rfind. You may use the member functions size, at and substr. Your function must be recursive.1. Let product(n,m) be a recursive method that computes the product of two positive integers, using only addition and subtraction. To make this method a recursive one, you are to make a) a base case when m = 1, b) a general case when m ≠ 1. For a general case, the return value should be n plus the result of a recursive call to the method product() with parameters n and m - 1. Write a short Java code for this method, along with a test program.
- Given the sequence, S2 = 1, 2, 4, 5, 7, 8, 10, 11, 13, 14, … Write a RECURSIVE method called “sequence2” that takes a single int parameter (n) and returns the int value of the nth element of the sequence S2. You will need to determine any base cases and a recursive case that describes the listed sequence. Use the following code to test your answers to questions 3 and 4the output should print the two sequences given (S & S2): public class TestSequences { public static void main(String[] args) { for(int i = 0; i < 10; i++) { System.out.print(sequence(i) + " "); // 2, 4, 6, 12, 22, 40, 74, 136, 250, 460 } System.out.println(); for(int i = 0; i < 10; i++) { System.out.print(sequence2(i) + " "); // 1, 2, 4, 5, 7, 8, 10, 11, 13, 14 } } // *** Your method for sequence here *** // *** Your method for sequences2 here *** } // end of TestSequences classCodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021Create a class Recursion. It will have two static methods: removeX and countSubstring and write each function recursively. Recursion class removeX The removeX function will take a String as a parameter. It will return a new String that is the same as the original String, but with all “x” characters removed. This method will be case insensitive. countSubstring The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. Create a Main class to test and run your Recursion class.
- Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a string and remove all occurrences of the word chicken and count how many chickens were removed. Keep in mind that removing a chicken might show a previously hidden chicken. You may find substring and indexOf useful. achickchickenen - removing the 1st chicken would leave achicken behindachicken - removing the 2nd chicken would leave a behindSample Data : itatfunitatchickenfunchchickchickenenickenchickchickfunchickenbouncetheballchickenSample Output : 01302T/F 7. The recursive procedure for solving the Towers of Hanoi can only be used if the number of discs parameter is 7 or less.1. Write a recursive method expFive(n) to compute y=5^n. For instance, if n is 0, y is 1. If n is 3, then y is 125. If n is 4, then y is 625. The recursive method cannot have loops. Then write a testing program to call the recursive method. If you run your program, the results should look like this: > run RecExpTest Enter a number: 3 125 >run RecExpTest Enter a number: 3125 2. For two integers m and n, their GCD(Greatest Common Divisor) can be computed by a recursive function. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Once m is 0, the function returns n. Once n is 0, the function returns m. If neither is 0, the function can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n. Although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. Meaning your code needs to follow the given algorithm. Then…