If we use the normal equation method to solve the linear least square (LS) problems Ax=b, where the null space of A is empty. It may the following properties, [1] The matrix AHA is invertible; [2] The matrix AHA is singular [3] The LS solution is (AHA)-¹ (AHb). We can definitely say that: (a) (b) [1], [2], [3] are all correct Only [1], [2] are correct Only [1], [3] are correct [1], [2], [3] are all incorrect (d)
If we use the normal equation method to solve the linear least square (LS) problems Ax=b, where the null space of A is empty. It may the following properties, [1] The matrix AHA is invertible; [2] The matrix AHA is singular [3] The LS solution is (AHA)-¹ (AHb). We can definitely say that: (a) (b) [1], [2], [3] are all correct Only [1], [2] are correct Only [1], [3] are correct [1], [2], [3] are all incorrect (d)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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