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MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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
Transcribed Image Text:In the simplex method, we have occasion to compute
the inverse of a
matrix for which only one column is different from that
of a matrix whose
inverse if already known. Suppose that we have a non-
singlar matrix B =
(b1, b2, . bn) and that B-1 is known. Now we
replace column r of B with
a and wish to compute the inverse of Ba = (b1, b
2, br-1, a, br+1, . . ., bn). If the columns of B
and Ba are viewed as two bases of En, then Ba is
obtained from B by changing a single vector in the
basis. Use this to derive the inverse of Ba as a function
of B-1. B-1 =
204
516
793
where the second column of B is replaced by a random
vector in R3
. You may read on elementary transformations, present
the theory and write a
code to generate the output.
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- Reduce the matrix -1 -2 -4 8. A 3= -1 -8 2 1 -4 ed row-echelon form. 9:45 9 Type here to search 口令 NG 3/18/ UPEEF (凸)arrow_forward-Make a 3 x 4 matrix with rank equal to 1. -Make a 3 x 4 matrix with nullity equal to 1.arrow_forwardShow that if A is square matrix that satisfies the equation 2 A² - A - I = O, then its inverse is A-¹ = 2 A-I. The equation 24² - A - I = O implies that ---Select--- ✓. It follows that ---Select--- ✓. Notice the last equation means that ---Select--- multiplied with A is the identity, which is what we wanted to prove.arrow_forward
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