Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Transcribed Image Text:If the motor exerts a force of F = (600 + 2s²)N on the
cable, determine the speed of the 100-kg crate when it
rises to s = 15 m. The crate is initially at rest on the
ground.
M
15 m
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- 2. Initially the 5-kg block is moving with a constant speed of 2 m/s around the circular path centered at 0 on the smooth horizontal plane. If a constant tangential force F = 5 N is applied to the block, determine its speed when t = 3 s. Neglect the size of the block. 1.5 m F = 5 N 2 m/sarrow_forwardThe crate, which has a mass of 160 kg, is subjected to the action of the two forces. If it is originally at rest, determine the distance it slides in order to attain a speed of 7 m/s. The coefficient of kinetic friction between the crate and the surface is μk = 0.2.arrow_forwardThe block has a mass of 40 kg and rests on the surface of the cart having a mass of 78 kg If the spring which is attached to the cart and not the block is compressed 0.2 m and the system is released from rest, determine the speed of the block with respect to the cart after the spring becomes undeformed. Neglect the mass of the wheels and the spring in the calculation. Also neglect friction. Take k = 310 N/marrow_forward
- The motor, M, pulls on the cable with a force F = (101² + 300)N, where t is in seconds. If the 100 kg crate is originally at rest at 1 = 0, determine its speed when t = 4 s. Hint: First find the time needed to begin lifting the crate.arrow_forward2. The 10-Ib block has a speed of 4 ft's when the force of F= (8t?) Ib is applied. Determine the velocity of the block when t= 2 s. The coefficient of kinetic friction at the surface is = 0.2. v = 4 ft/s F= (8°) lbarrow_forwardIf the force exerted on cable AB by the motor is F = ( 110 t 3/2 ) N, where tt is in seconds, determine the 55-kg crate's velocity when ttt = 5 s . The coefficients of static and kinetic friction between the crate and the ground are μs = 0.37 and μk = 0.29, respectively. Initially the crate is at rest. (Figure 1)arrow_forward
- The initially stationary 24-kg block is subjected to the time-varying force whose magnitude P is shown in the plot. Note that the force is zero for all times greater than 5 s. Determine the time t, at which the block comes to rest. P, N 24 kg 26° T Mk=0.43 Hg = 0.51 Answe: ts = i 173 S 5 t, sarrow_forward5. The 8-kg smooth collar has a speed of 5 m/s when it is at s = 0. Determine the maximum distance s it travels before it stops momentarily. The spring has an unstretched length of 2 m. -1.5 m- -3 m/s k = 100 N/marrow_forward
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