If an organism that is homozygous dominant is crossed with a heterozygote for that trait, the offspring will be _All of the dominant phenotype________________. All homozygous dominant Three-quarters of the dominant phenotype and one-quarter of the recessive phenotype Present in a 9:3:3:1 ratio All of the dominant phenotype All homozygous recessive
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- If an organism that is homozygous dominant is crossed with a heterozygote for that trait, the offspring will be _All of the dominant phenotype________________.
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All homozygous dominant
- Three-quarters of the dominant
phenotype and one-quarter of the recessive phenotype - Present in a 9:3:3:1 ratio
- All of the dominant phenotype
- All homozygous recessive
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- A man with a specific unusual genetic trait marries an unaffected woman. For each type of inheritance, place the pedigree that would result from the cross. Assume the trait is fully penetrant and rare. Autosomal recessive X-linked recessive Y-linked Autosomal dominant X-linked dominant |Unaffected male |Affected male OUnaffected female Affected female Answer Bank 오모오모A newly-married couple is thinking of having children. They are worried about their child having cystic fibrosis, a recessive disease that shows up in children with the genotype ff. Jake, the father is homozygous dominant with a genotype FF. Amy, the mother, is heterozygous with a genotype Ff. Should they be worried about their children having this disease? For full credit, discuss the probability of having each genotype (FF, Ff, and ff) in your explanation. You may first write and then RECORD YOUR ANSWER.Pedigree attached shows an autosomal recessive genetic disease. G is the normal allele and g is the disease-causing allele. Individual 1’s father is heterozygous (*) and his mother is homozygous dominant. Other individuals in the pedigree may be carriers, but are not marked. The question mark (?) indicates that you do not yet know anything about this individual’s phenotype with regard to the disease. part a) What is the probability that individuals 1 and 2 will have a child (5) who is a boy with the disease (the child is unborn and the sex is not yet known)? a)1/8 b)1/4 c)0 d)1/16 part b) What is the probability that the daughter (6) that individual 3 and 4 just had will have the disease? a)1/8 b)1/6 c)1/4 d)1/12
- Match the word or phrase to a correct statement about it. recessive allele [Choose ] [Choose a cross between 4 parents an individual with 1 dominant allele and 1 recessive allele an individual with 2 recessive alleles a phenotype made of 2 dominant alleles only expressed in the phenotype if it's the only kind of allele present a letter written in uppercase dominant allele homozygous dominant a genotype made of 2 dominant alleles a cross looking at 2 separate genes dihybrid Choose | carrier an individual with 2 recessive 99+The non-wild-type alleles are k (clipped wings), l (long tail), and m (magical powers). The parental stocks are homozygous doubly recessive flies of genotype k+/k+ · l/l · m/m and homozygous singly recessive flies of genotype k/k · l+/l+ · m+/m+. From this cross, triply heterozygous progeny of genotype k/k+ · l/l+ · m/m+ are obtained, and females of this genotype are testcrossed to triple recessives of genotype k/k · l/l · m/m. The genotypes determining the eight progeny types from this testcross (CROSS C) are shown here with their numbers, out of a total sample of 1,572 flies. What is the correct order of the genes? What number of progeny for each genotype would you predict in the case of independent assortment? What is a non-recombinant genotype? What is a genotype of a single crossover? What is a genotype of a double crossover? What is the longest distance between any of the two dragon alleles above? What is the shortest distance between any of the two dragon alleles above?…young couple is planning to have children. The male is heterozygous for Huntington’s disease and homozygous dominant for Tay-Sachs. The female is homozygous recessive for Huntington’s disease and heterozygous for Tay-Sachs. The couple is curious about the possibility and probability of their offspring inheriting Tay-Sachs and/or Huntington’s. For humans, Huntington’s disease is dominant (H) over the “normal” condition (h), and the “normal” condition is dominant (T) over Tay-Sachs (t). Complete a Punnett square for this cross and record the percent probabilities for genotypes and phenotypes of the offspring.
- A young couple went to see a genetic counselor because each had a sibling with cystic fibrosis. (Cysticfibrosis is a recessive disease, and neither member ofthe couple nor any of their four parents is affected.)a. What is the probability that the female of thiscouple is a carrier?b. What are the chances that their child will havecystic fibrosis?c. What is the probability that their child will be acarrier of the cystic fibrosis disease allele?Sickle cell anemia is inherited as an autosomal recessive condition. It also exhibits incomplete dominance in that the heterozygous genotype displays a mild form of the disease known as sickle cell trait while individuals with the homozygous recessive genotype have a severe form of SCA. A man who has severe sickle cell anemia marries a woman who suffers from a mild trait. What is the probabilitu they will have a child with severe SCA?What is the probability they will have a child with mild SCA? What is the probability they will have a normal child? Show ALL work using punnett squares.The following pedigree shows the inheritance of a rare genetic disorder. Determine the most likely mode of inheritance, and for exam practice (unmarked on the assignment) write a clear justification for your conclusion. Remember that some pedigrees don't provide sufficient data/information to discriminate between possibilities. If that is the case, select all the possible answers. I III Tb 2 3 1 1 3 autosomal dominant autosomal recessive Osex-linked dominant Osex-linked recessive O 2 H
- As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progenyParts a-c of this question address the crossing of parents with the following genotypes: A/a; B/b; C/c; D/d; E/e; F/f x a/a; b/b; c/c; d/d; e/e; f/f a. What is the probability that an F1 progeny that is homozygous recessive at every locus will be produced? For values greater than 0, please answer as a fraction. b. What is the probability that an F1 progeny that is homozygous dominant at every locus will be produced? For values greater than 0, please answer as a fraction. c. Would one of the parents in this cross be considered a test cross parent (tester)? Yes, the parent on the left, with genotype A/a; B/b; C/c; D/d; E/e; F/f would be the test cross parent (tester). Yes, the parent on the right, with genotype a/a; b/b; c/c; d/d; e/e; f/f would be the test cross parent (tester). Yes, both parents would be considered a test cross parent (tester) No, neither parent would be considered a test cross parent (tester) None of the above and I have explained my…tate.edu/d21/le/content/5003190/viewContent/44015425/View 8. Consider the following phenotype for hemophilia, a recessive X-linked blood clotting disorder, in decendents of Queen Victoria. Victoria is thought to have been a carrier for the recessive hemophilia allele. What is the probability that Princess Irene is also a carrier? Albert Victoria (1819-1901) Helena Leopold Alice of Hesse Empress Edward Beatrice Victoria VII Princess Duke of Christian Albany Kaiser George Wilhelm II Princess Frederick (Alexandra) Irene Alice of Athlone Victoria Leopold Maurice Eugenie (wife of Alfonso XIII) Alix Tsarina Nikolas II