College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A 14 Gram ovarian tumor is treated using a sodium phosphate in which the phosphorus atoms are the radioactive phosphorus 32 isotopes with half life of 14.3 days and which decays via beta emission with energy of 1.71Mev.Half of the sodium phosphate solution is absorbed by the tumor and deposits 9.0J of energy into it. The other half of the solution is dispersed through out the patients tissue and also depositing 9.0j energy into the 50kg of body tissue.
I. What dose in (gray and rem) that the tumor receives.
Ii. What is the dose in (mill gray and rem) that the tissue receives
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- 1.a. A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioative phosphorus-32 isotope with a half-life of 14.3 days and which decays via beta emision (RBE=1) with an energy of 1.71 MeV. Half of the sodium phosphate is absorbed by the tumor and deposits 9.0 J energy into it. The other half of the solution is absorbed throughout the patient's tissues, also depositing 9.0 J of energy into the 50.0 kg of body tissues. i. What is the dose ( in gray and rem) that the tumor receives? ii. What is the dose ( in milligray and rem) that the rest of the tissues receives? b. Photoelectrons from a material with a binding energy of 2.71 eV are ejected by 420-nm photons. Once ejected, how long does it take these electrons to travel 2.50cm to a detected device? c.The heating element in an electric kettle is rated as 2.0kW. If the waterin the kettle is at 1000.0 oC, what volume of water will be converted in to steam in…arrow_forwardWhat minimum energy E(min) is needed to remove a neutron from K40 and so convert it to K39? The atomic masses of the two isotopes are 39.964000 and 38.963708 u, respectively. E(min) = ? eVarrow_forwardA nucleus of 238 Np captures a thermal neutron to form a nucleus of 239 Np . What is the excitation energy ( to 1 dp ) in MeV for this process ?arrow_forward
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