Question
A 14-gram ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioactive phosphorus-32 isotope with a half-life of 14.3 days and which decays via beta emission (RBE=1) with an energy of 1.71MeV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 9.0J of energy into it. The other half of the solution is dispersed throughout the patient's tissues, also depositing 9.0J of energy into the 50.0kg of body tissues.
I). What is the dose ( in gray and rem) that the tumor receives?
ii). What is the dose ( in miligray and rem) that the rest of the tissues receives?
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