I have no problem with the solution method, but my issue lies in drawing the small triangle. Can you facilitate the process of drawing it? Determine the magnitude of gm for a JFET with IDss = 8 mA and Vp = -4 V at the following de bias points: (a) VGs=-0.5 V. (b) VGS -1.5 V. (c) VGS-2.5 V. Solution The transfer characteristics are generated as Fig. 9.2 using the procedure defined in Chapter 6. Each operating point is then identified and a tangent line is drawn at each point to best reflect the slope of the transfer curve in this region. An appropriate in- crement is then chosen for VGs to reflect a variation to either side of each Q-point. Equation (9.2) is then applied to determine gm. AID 2.1 mA E (a) gm = = 3.5 mS AVGS 0.6 V Alp 1.8 mA (b) gm = =2.57 mS AVGS 0.7 V (c) gm Alp AVGS 1.5 mA = = 1.5 mS 1.0 V Note the decrease in gm as VGs approaches Vp. AID (mA) 8 7 8mat-0.5 V 6 2.1 mA ID=8 mA mA (1- Vas) 2 5 0.6 V 4 Bat-1.5 V 1.8 mA-3 2 8mat-2.5 V 0.7 V 1.5 mA 1 1.0 V 0 VGS (V) Figure 9.2 Calculating gm at various bias points.

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I hope you can clarify how to draw a small triangle accurately.
I have no problem with the solution method, but my
issue lies in drawing the small triangle. Can you
facilitate the process of drawing it?
Determine the magnitude of gm for a JFET with IDss = 8 mA and Vp = -4 V at the
following de bias points:
(a) VGs=-0.5 V.
(b) VGS -1.5 V.
(c) VGS-2.5 V.
Solution
The transfer characteristics are generated as Fig. 9.2 using the procedure defined in
Chapter 6. Each operating point is then identified and a tangent line is drawn at each
point to best reflect the slope of the transfer curve in this region. An appropriate in-
crement is then chosen for VGs to reflect a variation to either side of each Q-point.
Equation (9.2) is then applied to determine gm.
AID 2.1 mA
E
(a) gm =
= 3.5 mS
AVGS
0.6 V
Alp
1.8 mA
(b) gm =
=2.57 mS
AVGS
0.7 V
(c) gm
Alp
AVGS
1.5 mA
=
= 1.5 mS
1.0 V
Note the decrease in gm as VGs approaches Vp.
AID (mA)
8
7
8mat-0.5 V
6
2.1 mA
ID=8 mA
mA (1- Vas) 2
5
0.6 V
4
Bat-1.5 V
1.8 mA-3
2
8mat-2.5 V
0.7 V
1.5 mA
1
1.0 V
0
VGS (V)
Figure 9.2 Calculating gm at
various bias points.
Transcribed Image Text:I have no problem with the solution method, but my issue lies in drawing the small triangle. Can you facilitate the process of drawing it? Determine the magnitude of gm for a JFET with IDss = 8 mA and Vp = -4 V at the following de bias points: (a) VGs=-0.5 V. (b) VGS -1.5 V. (c) VGS-2.5 V. Solution The transfer characteristics are generated as Fig. 9.2 using the procedure defined in Chapter 6. Each operating point is then identified and a tangent line is drawn at each point to best reflect the slope of the transfer curve in this region. An appropriate in- crement is then chosen for VGs to reflect a variation to either side of each Q-point. Equation (9.2) is then applied to determine gm. AID 2.1 mA E (a) gm = = 3.5 mS AVGS 0.6 V Alp 1.8 mA (b) gm = =2.57 mS AVGS 0.7 V (c) gm Alp AVGS 1.5 mA = = 1.5 mS 1.0 V Note the decrease in gm as VGs approaches Vp. AID (mA) 8 7 8mat-0.5 V 6 2.1 mA ID=8 mA mA (1- Vas) 2 5 0.6 V 4 Bat-1.5 V 1.8 mA-3 2 8mat-2.5 V 0.7 V 1.5 mA 1 1.0 V 0 VGS (V) Figure 9.2 Calculating gm at various bias points.
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