HW7_Question 4. Considering a symmetric stenosis (narrowing of blood vessel) as shown in the following figure. Assume that the velocity profile within the stenosis of radius R(z) has the same shape as the profile outside the stenosis and is represented as: Vz (r) = vmax (1 – 5) Outside the stenosis, the radius R equals R, and the maximum velocity is constant. Within the stenosis, the radius of the fluid channel R(z) equals R(z) = Ro {1 –0.5[1- R(z)t The origin of the z axis is the midpoint of the stenosis. The volumetric flow rate Q can be 2n R calculated from Q = S S vzr dr d0 0 0 (b) Develop an expression for Vmax in the stenosis in term of the volumetric flow rate Q, cylindrical tube of radius Ro and distance along the stenosis z/L. Evaluate Vmax at z = O when Ro =0.5 cm, L = 1cm, Q = 4L/min.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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HW7_Question 4. Considering a symmetric stenosis (narrowing of blood vessel) as shown in the
following figure. Assume that the velocity profile within the stenosis of radius R(z) has the same shape as
the profile outside the stenosis and is represented as:
vz (r) = vmax (1 - 5)
Outside the stenosis, the radius R equals R, and the maximum velocity is constant. Within the
stenosis, the radius of the fluid channel R(z) equals
R(z) = Ro {1 – 0.5[1 – 4(÷)*105}
R(z)t
Ro
The origin of the z axis is the midpoint of the stenosis. The volumetric flow rate Q can be
2n R
calculated from Q = [ S ver dr de
(b) Develop an expression for Vmax in the stenosis in term of the volumetric flow rate Q, cylindrical tube
of radius Ro and distance along the stenosis z/L. Evaluate Vmax at z = 0 when Ro =0.5 cm, L = 1cm, Q =
4L/min.
Transcribed Image Text:HW7_Question 4. Considering a symmetric stenosis (narrowing of blood vessel) as shown in the following figure. Assume that the velocity profile within the stenosis of radius R(z) has the same shape as the profile outside the stenosis and is represented as: vz (r) = vmax (1 - 5) Outside the stenosis, the radius R equals R, and the maximum velocity is constant. Within the stenosis, the radius of the fluid channel R(z) equals R(z) = Ro {1 – 0.5[1 – 4(÷)*105} R(z)t Ro The origin of the z axis is the midpoint of the stenosis. The volumetric flow rate Q can be 2n R calculated from Q = [ S ver dr de (b) Develop an expression for Vmax in the stenosis in term of the volumetric flow rate Q, cylindrical tube of radius Ro and distance along the stenosis z/L. Evaluate Vmax at z = 0 when Ro =0.5 cm, L = 1cm, Q = 4L/min.
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