However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k

Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter12: The Solid State
Section: Chapter Questions
Problem 6P
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In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of

 

and an adjacent C-H bond is at the direction

.

results to an angular bond of approximately 109o for a static frozen molecule. 

However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be

A = 0.93i + 0.91j + 1.09k

B = 1.02i + -0.99j + -1.08k

In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of
A= î +Î+k
and an adjacent C-H bond is at the direction
B=î-j-R.
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy
analysis, the adjacent bond vectors was found to be
A = 0.93i + 0.91j + 1.09k
B = 1.02i + -0.99j + -1.08k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.
Transcribed Image Text:In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= î +Î+k and an adjacent C-H bond is at the direction B=î-j-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
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