In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î +ĵ +k and an adjacent C-H bond is at the direction B=î-Î-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.88i + 1.05j + 0.94k B = 0.95i + -0.91j + -0.86k What is the angle (in degrees) between the bonds based on this new data?

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In the methane molecule, CHA, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of
A= î +ĵ +R
and an adjacent C-H bond is at the direction
B=î-Î-R.
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy
analysis, the adjacent bond vectors was found to be
A = 0.88i + 1.05j + 0.94k
B = 0.95i + -0.91j + -0.86k
What is the angle (in degrees) between the bonds based on this new data?
Transcribed Image Text:In the methane molecule, CHA, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= î +ĵ +R and an adjacent C-H bond is at the direction B=î-Î-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.88i + 1.05j + 0.94k B = 0.95i + -0.91j + -0.86k What is the angle (in degrees) between the bonds based on this new data?
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