How much heat would be required to convert 390 g of solid benzene, C6H6 (s), at 5.5°C into benzene vapor, C6H6 (g), at 120.0°C? mp of C6H6  (s) = 5.5oC                       molar heat of fusion at 5.5°C = 9.92 kJ/mol bp of C6H6  (l) = 80.1°C                        molar heat of vaporization at 80.1°C = 30.8 kJ/mol molar heat capacity of C6H6  (l) = 136 J/mol-°C molar heat capacity of C6H6  (g) = 81.6 J/mol-°C     106 kJ     158 kJ     53.kJ     262.kJ     5049 kJ

A cube of solid benzene (C6H6; M = 78.11 g/mol) at its melting point and weighing 8.90 g is placed in 21.6 g of water at 39.0 °C. Given that the heat of fusion of benzene is 9.92 kJ/mol, to what temperature will the water have cooled by the time all of the benzene has melted. You can assume that the benzene remains at its melting point.

The heat of fusion for a material can be found by AHfus = m x Cp x AT where AHfus is the heat of fusion per gram, m is the mass of the solid substance being melted, C, is the specific heat of the surrounding medium, and ATis the change in the temperature of the surrounding medium as the solid melts. Calculate the heat of fusion of a 10.00-g piece of Substance X. Use 4.18 J/g-° C as the specific heat, and assume a AT of 10.00 °C. Express your answer to three significant figures (units of J/g) 41.8 418 O 4.18

Calculate the energy released as heat when 18.7 g of liquid mercury at 25.00 °C is converted to solid mercury at its melting point. heat capacity of Hg(1) Constants for mercury at 1 atm melting point enthalpy of fusion 28.0 J/(mol-K) # 234.32 K 2.29 kJ/mol 9 = MacBook Pro