How many grams of nitric acid , HNO3, are required to neutralize (completely react with) 4.30 g of Ca(OH)2 according to the acid-base reaction: 2 HNO,(aq) + Ca(OH)2(aq) 2 H,0(1) + Ca(NO,)2(aq)

Sodium hydrogen carbonate (NaHCO3), also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HCI), which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO, neutralizes excess HCI through this reaction: HCl(aq) + NaHCO3(aq) NaCl(aq) + H₂O(1) + CO₂(g) The CO₂ gas produced is what makes you burp after drinking the solution. Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 200 ml of a 0.050 M HCI solution. What mass of NaHCO, would he need to ingest to neutralize this much HCI? Be sure your answer has the correct number of significant digits. X

Complete the following reaction and balance it. Fe(OH)3(aq) + HCl(aq) →       a)  FeCl3(aq)+ 3 H2O(l)   b)  FeCl(aq) + H2O(l)   c)  Fe(aq) + HOCl(aq)   d)  FeCl(aq) + 3 OH–(aq)   e)  H2O(l) + FeCl2(aq)

Calculate the molar concentration HCl when 250 mL of 0.10 M HCl is mixed with 150 mL of 0.10 M NaOH in a beaker.                    HCl (aq)  + NaOH (aq)   →    NaCl (aq)   + H2O (l)

a Ammonium chloride and rubidium acetate, RbCH, CO₂, are mixed in water. Choose a balanced equation for the acid-base reaction that could, in principle, occur. O RbCH3CO₂ (s)+NH, Cl(s) + H₂O() = Rb+ (aq) + CH3CO₂¯(aq) +NH, +(aq) +Cl¯(aq) OCH3CO₂ (aq) + NH4+ (aq) CH3CO₂H(aq) + NH3 (aq) RbCH, CO₂ (aq) + NH4Cl(aq) NH₂CH3 CO₂ (aq) + RbCl(aq)

7. Identify the given reactions as acid-base, redox, or precipitation reactions. 3NaOH(aq)+FeCl3(aq)=Fe(OH)3(s)+3NaCl(aq) LiOH(aq)+HCl(aq)=H2O(l) + LiCl(aq) 2H2(g)+ O2(g)=2H2O(g)

Molarity of vinegar solution is .8 M

Identify the correct net ionic equation for the reaction that occurs when solutions of HF and KOH are mixed. Multiple Choice: HF(aq) + OH-(aq) → H2O(l) + F-(aq) HF(aq) + KOH(aq) → H2O(l) + KF(s) H+(aq) + KOH(aq) → H2O(l) + K+(aq) H+(aq) + OH-(aq) → H2O(l) HF(aq) + KOH(s) → H2O(l) + KF(aq)