How many grams of N2 are needed to make 444 g of NBr3 ?  N2   +   3 Br2   →   2 NBr3   +   44.0 kJ              The molar mass of NBr3 is 253.719 g and the molar mass of N2 is 28.013 g

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Chapter4: Types Of Chemical Reactions And Solution Stoichiometry
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Problem 16Q: A student wants to prepare 1.00 L of a 1.00-M solution of NaOH (molar mass = 40.00 g/mol). If solid...
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How many grams of N2 are needed to make 444 g of NBr3 ?

 N2   +   3 Br2   →   2 NBr3   +   44.0 kJ             

The molar mass of NBr3 is 253.719 g and the molar mass of N2 is 28.013 g

                       _______________ mol NBr3                                                                                  

(444 g NBr3)(–––––––––––––––––––––––––)  = ______________  mol NBr3

                       ____________________ g NBr3   

                                                                              

                                                       _______________ mol N2  

 _______________ mol NBr3 (–––––––––––––––––––––––––) =  ___________---- mol N2

                                                       _________________ mol NBr3 

 

                                                        _______________  g N2

_____________________ mol N2 (–––––––––––––––––––––––––) = ___________________  g N2

                                                      __________________ mol N2

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